| Exam Board | Edexcel |
|---|---|
| Module | M1 (Mechanics 1) |
| Year | 2022 |
| Session | June |
| Marks | 7 |
| Paper | Download PDF ↗ |
| Mark scheme | Download PDF ↗ |
| Topic | Newton's laws and connected particles |
| Type | Two connected particles, horizontal surface |
| Difficulty | Moderate -0.8 This is a straightforward connected particles problem requiring application of Newton's second law to two bodies separately. Students identify forces, write F=ma equations for tractor and block, and solve simultaneously - a standard M1 exercise with clear given values and routine algebraic manipulation. Part (b) tests basic understanding of modeling assumptions. |
| Spec | 3.03d Newton's second law: 2D vectors3.03k Connected particles: pulleys and equilibrium |
| VIIHV SIHI NI IIIHM IONOOC | VIAV SIMI NI III IM I O N OA | VI4V SIHI NI JIIIM ION OC |
| Answer | Marks | Guidance |
|---|---|---|
| Answer/Working | Marks | Guidance |
| \(7400 - 200 - 6000 = 6000a\) | M1A1 | Correct no. of terms, condone sign errors (use mass to determine which equation is being attempted). \(6000\) N must be used as the tension to earn an M mark |
| \(7400 - 200 - R = 8000a\) | M1A1 | Correct no. of terms, condone sign errors |
| \(6000 - R = 2000a\) | Any two of these three equations | |
| \(R = 5600\) | DM1A1 | DM1: Solve for \(R\), dependent on both M marks. A1 cao. N.B. If consistently using tonnes: max M1A0M1A0M1A1 |
| Answer | Marks | Guidance |
|---|---|---|
| Answer/Working | Marks | Guidance |
| Same acceleration for the tractor and the block | B1 | Any equivalent statement e.g. 'both have the same acceleration'. Need to say 'both' or mention the tractor and the block. Allow 'same acceleration throughout the system' and 'both particles have the same acceleration'. B0 if extra wrong answers included |
# Question 3:
## Part 3(a):
| Answer/Working | Marks | Guidance |
|---|---|---|
| $7400 - 200 - 6000 = 6000a$ | M1A1 | Correct no. of terms, condone sign errors (use mass to determine which equation is being attempted). $6000$ N must be used as the tension to earn an M mark |
| $7400 - 200 - R = 8000a$ | M1A1 | Correct no. of terms, condone sign errors |
| $6000 - R = 2000a$ | | Any two of these three equations |
| $R = 5600$ | DM1A1 | DM1: Solve for $R$, dependent on both M marks. A1 cao. N.B. If consistently using tonnes: max M1A0M1A0M1A1 |
## Part 3(b):
| Answer/Working | Marks | Guidance |
|---|---|---|
| Same acceleration for the tractor and the block | B1 | Any equivalent statement e.g. 'both have the same acceleration'. Need to say 'both' or mention the tractor and the block. Allow 'same acceleration throughout the system' and 'both particles have the same acceleration'. B0 if extra wrong answers included |
---3. A tractor of mass 6 tonnes is dragging a large block of mass 2 tonnes along rough horizontal ground. The cable connecting the tractor to the block is horizontal and parallel to the direction of motion.
The cable is modelled as being light and inextensible.\\
The driving force of the tractor is 7400 N and the resistance to the motion of the tractor is 200 N . The resistance to the motion of the block is $R$ newtons, where $R$ is a constant.
Given that the tension in the cable is 6000 N and the tractor is accelerating,
\begin{enumerate}[label=(\alph*)]
\item find the value of $R$.
\item State how you have used the fact that the cable is modelled as being inextensible.\\
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VIIHV SIHI NI IIIHM IONOOC & VIAV SIMI NI III IM I O N OA & VI4V SIHI NI JIIIM ION OC \\
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Q
\end{enumerate}
\hfill \mbox{\textit{Edexcel M1 2022 Q3 [7]}}