Edexcel M1 2014 June — Question 1 5 marks

Exam BoardEdexcel
ModuleM1 (Mechanics 1)
Year2014
SessionJune
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicMomentum and Collisions
TypeDirect collision, find mass
DifficultyModerate -0.8 This is a straightforward M1 momentum conservation problem requiring direct application of the principle with given values. Part (a) uses conservation of momentum with one unknown, part (b) applies impulse-momentum theorem. Both are standard textbook exercises with no problem-solving insight needed, making it easier than average A-level questions.
Spec6.03b Conservation of momentum: 1D two particles6.03e Impulse: by a force

  1. Two small smooth balls \(A\) and \(B\) have mass 0.6 kg and 0.9 kg respectively. They are moving in a straight line towards each other in opposite directions on a smooth horizontal floor and collide directly. Immediately before the collision the speed of \(A\) is \(v \mathrm {~m} \mathrm {~s} ^ { - 1 }\) and the speed of \(B\) is \(2 \mathrm {~m} \mathrm {~s} ^ { - 1 }\). The speed of \(A\) is \(2 \mathrm {~m} \mathrm {~s} ^ { - 1 }\) immediately after the collision and \(B\) is brought to rest by the collision.
Find
  1. the value of \(v\),
  2. the magnitude of the impulse exerted on \(A\) by \(B\) in the collision.

Question 1:
Part (a)
AnswerMarks Guidance
Answer/WorkingMarks Guidance Notes
\(0.9 \times 2 - 0.6v = 0 + 0.6 \times 2\)M1 Equation with all terms – condone "0" missing. Terms must be of the form \(mv\), but condone sign errors. Condone \(g\) present as a common factor.
(correct unsimplified equation)A1 Correct unsimplified equation
\(v = 1\)A1 (3)
Part (b)
AnswerMarks Guidance
Answer/WorkingMarks Guidance Notes
\(I = 0.6(v+2) = 1.8\) N s or \(I = 0.9 \times 2 = 1.8\) N sM1 Change in momentum of \(A\) or of \(B\). Condone sign slips and negative answer. No \(g\).
\(1.8\) N sA1 (2) 1.8 only (or exact equivalent). From correct work only.
> Note: Watch out for fortuitous answers in (b); \(v = 5\) from (a) used in (b) will score at most M1A0 in (b).
Total: [5]
# Question 1:

## Part (a)

| Answer/Working | Marks | Guidance Notes |
|---|---|---|
| $0.9 \times 2 - 0.6v = 0 + 0.6 \times 2$ | M1 | Equation with all terms – condone "0" missing. Terms must be of the form $mv$, but condone sign errors. Condone $g$ present as a common factor. |
| (correct unsimplified equation) | A1 | Correct unsimplified equation |
| $v = 1$ | A1 (3) | |

## Part (b)

| Answer/Working | Marks | Guidance Notes |
|---|---|---|
| $I = 0.6(v+2) = 1.8$ N s  or  $I = 0.9 \times 2 = 1.8$ N s | M1 | Change in momentum of $A$ or of $B$. Condone sign slips and negative answer. No $g$. |
| $1.8$ N s | A1 (2) | 1.8 only (or exact equivalent). From correct work only. |

> **Note:** Watch out for fortuitous answers in (b); $v = 5$ from (a) used in (b) will score at most M1A0 in (b).

**Total: [5]**

---
\begin{enumerate}
  \item Two small smooth balls $A$ and $B$ have mass 0.6 kg and 0.9 kg respectively. They are moving in a straight line towards each other in opposite directions on a smooth horizontal floor and collide directly. Immediately before the collision the speed of $A$ is $v \mathrm {~m} \mathrm {~s} ^ { - 1 }$ and the speed of $B$ is $2 \mathrm {~m} \mathrm {~s} ^ { - 1 }$. The speed of $A$ is $2 \mathrm {~m} \mathrm {~s} ^ { - 1 }$ immediately after the collision and $B$ is brought to rest by the collision.
\end{enumerate}

Find\\
(a) the value of $v$,\\
(b) the magnitude of the impulse exerted on $A$ by $B$ in the collision.\\

\hfill \mbox{\textit{Edexcel M1 2014 Q1 [5]}}