Edexcel M1 2014 June — Question 6 13 marks

Exam BoardEdexcel
ModuleM1 (Mechanics 1)
Year2014
SessionJune
Marks13
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicConstant acceleration (SUVAT)
TypeMulti-phase journey: find unknown speed or time
DifficultyModerate -0.3 This is a straightforward multi-stage SUVAT question where all accelerations and times are given explicitly. Students apply v=u+at and s=ut+½at² systematically to each stage with no problem-solving required beyond careful bookkeeping. The structure is standard for M1, though the multiple stages and final distance constraint add minor computational complexity above the most basic exercises.
Spec3.02d Constant acceleration: SUVAT formulae

  1. A car starts from rest at a point \(A\) and moves along a straight horizontal road. The car moves with constant acceleration \(1.5 \mathrm {~m} \mathrm {~s} ^ { - 2 }\) for the first 8 s . The car then moves with constant acceleration \(0.8 \mathrm {~m} \mathrm {~s} ^ { - 2 }\) for the next 20 s . It then moves with constant speed for \(T\) seconds before slowing down with constant deceleration \(2.8 \mathrm {~m} \mathrm {~s} ^ { - 2 }\) until it stops at a point \(B\).
    1. Find the speed of the car 28 s after leaving \(A\).
    2. Sketch, in the space provided, a speed-time graph to illustrate the motion of the car as it travels from \(A\) to \(B\).
    3. Find the distance travelled by the car during the first 28 s of its journey from \(A\).
    The distance from \(A\) to \(B\) is 2 km .
  2. Find the value of \(T\).

Question 6:
Part (a):
AnswerMarks Guidance
AnswerMarks Guidance
\(v_1 = 8 \times 1.5\ (=12)\)M1 Use of \(v = u + at\) or equivalent for \(t = 8\)
\(v_2 = 12 + 0.8 \times 20\)M1 Follow their 12
\(v_2 = 28\) m s\(^{-1}\)A1(3)
Part (b):
AnswerMarks Guidance
AnswerMarks Guidance
Correct shape (trapezium with triangle at start)B1 Shape
Numbers 8, 28; 12, 28 indicatedB1ft(2) nos: 8,28; 12,28 indicated. Follow their 12, 28
Part (c):
AnswerMarks Guidance
AnswerMarks Guidance
First 8 s: dist \(= \frac{1}{2} \times 8 \times 12\ (= 48)\)M1 Correct method for distance for the triangle (0-8) or the trapezium (8-28)
A1ftFollow their 12
Next 20 s: dist \(= \frac{1}{2}(12+28) \times 20\ (= 400)\)A1ft Follow their 12, 28
Total dist \(= 448\) mA1(4) Correct answer only (cao)
Part (d):
AnswerMarks Guidance
AnswerMarks Guidance
\(0 = 28^2 - 2 \times 2.8s\)M1 Find area of right hand triangle or an expression in \(T\) for the trapezium (rectangle + triangle)
\(s = \frac{28^2}{2 \times 2.8}\ (= 140)\)A1ft Follow their 28
\(448 + 140 + 28T = 2000\)DM1 Form an equation in \(T\) for their 16, 448 and 140
\(T = \frac{2000 - 448 - 140}{28} = 50.4\)A1(4) Or better (50.42857...) Accept 50
Total: [13]
# Question 6:

## Part (a):
| Answer | Marks | Guidance |
|--------|-------|----------|
| $v_1 = 8 \times 1.5\ (=12)$ | M1 | Use of $v = u + at$ or equivalent for $t = 8$ |
| $v_2 = 12 + 0.8 \times 20$ | M1 | Follow their 12 |
| $v_2 = 28$ m s$^{-1}$ | A1(3) | |

## Part (b):
| Answer | Marks | Guidance |
|--------|-------|----------|
| Correct shape (trapezium with triangle at start) | B1 | Shape |
| Numbers 8, 28; 12, 28 indicated | B1ft(2) | nos: 8,28; 12,28 indicated. Follow their 12, 28 |

## Part (c):
| Answer | Marks | Guidance |
|--------|-------|----------|
| First 8 s: dist $= \frac{1}{2} \times 8 \times 12\ (= 48)$ | M1 | Correct method for distance for the triangle (0-8) or the trapezium (8-28) |
| | A1ft | Follow their 12 |
| Next 20 s: dist $= \frac{1}{2}(12+28) \times 20\ (= 400)$ | A1ft | Follow their 12, 28 |
| Total dist $= 448$ m | A1(4) | Correct answer only (cao) |

## Part (d):
| Answer | Marks | Guidance |
|--------|-------|----------|
| $0 = 28^2 - 2 \times 2.8s$ | M1 | Find area of right hand triangle or an expression in $T$ for the trapezium (rectangle + triangle) |
| $s = \frac{28^2}{2 \times 2.8}\ (= 140)$ | A1ft | Follow their 28 |
| $448 + 140 + 28T = 2000$ | DM1 | Form an equation in $T$ for their 16, 448 and 140 |
| $T = \frac{2000 - 448 - 140}{28} = 50.4$ | A1(4) | Or better (50.42857...) Accept 50 |

**Total: [13]**

---
\begin{enumerate}
  \item A car starts from rest at a point $A$ and moves along a straight horizontal road. The car moves with constant acceleration $1.5 \mathrm {~m} \mathrm {~s} ^ { - 2 }$ for the first 8 s . The car then moves with constant acceleration $0.8 \mathrm {~m} \mathrm {~s} ^ { - 2 }$ for the next 20 s . It then moves with constant speed for $T$ seconds before slowing down with constant deceleration $2.8 \mathrm {~m} \mathrm {~s} ^ { - 2 }$ until it stops at a point $B$.\\
(a) Find the speed of the car 28 s after leaving $A$.\\
(b) Sketch, in the space provided, a speed-time graph to illustrate the motion of the car as it travels from $A$ to $B$.\\
(c) Find the distance travelled by the car during the first 28 s of its journey from $A$.
\end{enumerate}

The distance from $A$ to $B$ is 2 km .\\
(d) Find the value of $T$.\\

\hfill \mbox{\textit{Edexcel M1 2014 Q6 [13]}}