Edexcel M2 2022 January — Question 5 12 marks

Exam BoardEdexcel
ModuleM2 (Mechanics 2)
Year2022
SessionJanuary
Marks12
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicMoments
TypeRod on smooth peg or cylinder
DifficultyStandard +0.3 This is a standard M2 moments question with straightforward geometry (Pythagoras), taking moments about a point, and resolving forces. Part (a) is immediate from Pythagoras, part (b) requires taking moments about A (a routine technique), and part (c) involves standard force resolution. The question is slightly easier than average because the geometry is given clearly and the methods are textbook-standard with no novel insight required.
Spec3.04a Calculate moments: about a point3.04b Equilibrium: zero resultant moment and force6.04e Rigid body equilibrium: coplanar forces

5. A smooth solid hemisphere is fixed with its flat surface in contact with rough horizontal ground. The hemisphere has centre \(O\) and radius \(5 a\).
A uniform rod \(A B\), of length \(16 a\) and weight \(W\), rests in equilibrium on the hemisphere with end \(A\) on the ground. The rod rests on the hemisphere at the point \(C\), where \(A C = 12 a\) and angle \(C A O = \alpha\), as shown in Figure 1. Points \(A , C , B\) and \(O\) all lie in the same vertical plane.
  1. Explain why \(A O = 13 a\) The normal reaction on the rod at \(C\) has magnitude \(k W\)
  2. Show that \(k = \frac { 8 } { 13 }\) The resultant force acting on the rod at \(A\) has magnitude \(R\) and acts upwards at \(\theta ^ { \circ }\) to the horizontal.
  3. Find
    1. an expression for \(R\) in terms of \(W\)
    2. the value of \(\theta\) (8) 5 \begin{figure}[h]
      \captionsetup{labelformat=empty} \caption{Figure 1} \includegraphics[alt={},max width=\textwidth]{0762451f-b951-4d66-9e01-61ecb7b30d95-16_426_1001_125_475}
      \end{figure} . T a and angle \(C A O = \alpha\), as shown in Figure 1.
      Points \(A , C , B\) and \(O\) all lie in the same vertical plane.
      1. Explain why \(A O = 13 a\)

5.

A smooth solid hemisphere is fixed with its flat surface in contact with rough horizontal ground. The hemisphere has centre $O$ and radius $5 a$.\\
A uniform rod $A B$, of length $16 a$ and weight $W$, rests in equilibrium on the hemisphere with end $A$ on the ground. The rod rests on the hemisphere at the point $C$, where $A C = 12 a$ and angle $C A O = \alpha$, as shown in Figure 1.

Points $A , C , B$ and $O$ all lie in the same vertical plane.
\begin{enumerate}[label=(\alph*)]
\item Explain why $A O = 13 a$

The normal reaction on the rod at $C$ has magnitude $k W$
\item Show that $k = \frac { 8 } { 13 }$

The resultant force acting on the rod at $A$ has magnitude $R$ and acts upwards at $\theta ^ { \circ }$ to the horizontal.
\item Find
\begin{enumerate}[label=(\roman*)]
\item an expression for $R$ in terms of $W$
\item the value of $\theta$\\
(8)

5

\begin{figure}[h]
\begin{center}
\captionsetup{labelformat=empty}
\caption{Figure 1}
  \includegraphics[alt={},max width=\textwidth]{0762451f-b951-4d66-9e01-61ecb7b30d95-16_426_1001_125_475}
\end{center}
\end{figure}

. T a and angle $C A O = \alpha$, as shown in Figure 1.\\
Points $A , C , B$ and $O$ all lie in the same vertical plane.\\
(a) Explain why $A O = 13 a$
\end{enumerate}\end{enumerate}

\hfill \mbox{\textit{Edexcel M2 2022 Q5 [12]}}