Edexcel M2 2022 January — Question 2 9 marks

Exam BoardEdexcel
ModuleM2 (Mechanics 2)
Year2022
SessionJanuary
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicAdvanced work-energy problems
TypeEngine power on road constant/variable speed
DifficultyStandard +0.3 This is a standard M2 mechanics problem requiring application of P=Fv for constant speed (part a) and work-energy principle (part b). The calculations are straightforward with clearly defined forces and no conceptual surprises, making it slightly easier than average for M2 level.
Spec6.02a Work done: concept and definition6.02b Calculate work: constant force, resolved component6.02i Conservation of energy: mechanical energy principle6.02k Power: rate of doing work6.02l Power and velocity: P = Fv

2. A car of mass 600 kg tows a trailer of mass 200 kg up a hill along a straight road that is inclined at angle \(\theta\) to the horizontal, where \(\sin \theta = \frac { 1 } { 20 }\). The trailer is attached to the car by a light inextensible towbar. The resistance to the motion of the car from non-gravitational forces is modelled as a constant force of magnitude 150 N . The resistance to the motion of the trailer from non-gravitational forces is modelled as a constant force of magnitude 300 N . When the engine of the car is working at a constant rate of \(P \mathrm {~kW}\) the car and the trailer have a constant speed of \(15 \mathrm {~m} \mathrm {~s} ^ { - 1 }\)
  1. Find the value of \(P\). Later, at the instant when the car and the trailer are travelling up the hill with a speed of \(20 \mathrm {~m} \mathrm {~s} ^ { - 1 }\), the towbar breaks. When the towbar breaks the trailer is at the point \(X\). The trailer continues to travel up the hill before coming to instantaneous rest at the point \(Y\). The resistance to the motion of the trailer from non-gravitational forces is again modelled as a constant force of magnitude 300 N .
  2. Use the work-energy principle to find the distance \(X Y\).
    VIIV SIHI NI III M I0N 00 :

2. A car of mass 600 kg tows a trailer of mass 200 kg up a hill along a straight road that is inclined at angle $\theta$ to the horizontal, where $\sin \theta = \frac { 1 } { 20 }$. The trailer is attached to the car by a light inextensible towbar. The resistance to the motion of the car from non-gravitational forces is modelled as a constant force of magnitude 150 N . The resistance to the motion of the trailer from non-gravitational forces is modelled as a constant force of magnitude 300 N .

When the engine of the car is working at a constant rate of $P \mathrm {~kW}$ the car and the trailer have a constant speed of $15 \mathrm {~m} \mathrm {~s} ^ { - 1 }$
\begin{enumerate}[label=(\alph*)]
\item Find the value of $P$.

Later, at the instant when the car and the trailer are travelling up the hill with a speed of $20 \mathrm {~m} \mathrm {~s} ^ { - 1 }$, the towbar breaks. When the towbar breaks the trailer is at the point $X$. The trailer continues to travel up the hill before coming to instantaneous rest at the point $Y$. The resistance to the motion of the trailer from non-gravitational forces is again modelled as a constant force of magnitude 300 N .
\item Use the work-energy principle to find the distance $X Y$.\\

VIIV SIHI NI III M I0N 00 :
\end{enumerate}

\hfill \mbox{\textit{Edexcel M2 2022 Q2 [9]}}