Edexcel M1 2016 June — Question 2 6 marks

Exam BoardEdexcel
ModuleM1 (Mechanics 1)
Year2016
SessionJune
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicNewton's laws and connected particles
TypeLift with passenger or load
DifficultyModerate -0.8 This is a straightforward application of Newton's second law to a two-body system with constant acceleration. Part (a) requires F=ma for the combined system (T - 2g = 2×0.5), and part (b) requires considering forces on the brick alone (R - 1.5g = 1.5×0.5). Both are standard textbook exercises with clear setup and routine calculation, making this easier than average for M1.
Spec3.03c Newton's second law: F=ma one dimension3.03d Newton's second law: 2D vectors

2. \begin{figure}[h]
\includegraphics[alt={},max width=\textwidth]{d408dd83-c5b2-4e55-b5c1-3e7f3faadbcb-04_327_255_283_847} \captionsetup{labelformat=empty} \caption{Figure 1}
\end{figure} A vertical rope \(A B\) has its end \(B\) attached to the top of a scale pan. The scale pan has mass 0.5 kg and carries a brick of mass 1.5 kg , as shown in Figure 1. The scale pan is raised vertically upwards with constant acceleration \(0.5 \mathrm {~m} \mathrm {~s} ^ { - 2 }\) using the rope \(A B\). The rope is modelled as a light inextensible string.
  1. Find the tension in the rope \(A B\).
  2. Find the magnitude of the force exerted on the scale pan by the brick.

Question 2:
Part (a)
AnswerMarks Guidance
WorkingMarks Notes
\(T - 0.5g - 1.5g = 2 \times 0.5\)M1 A1 Equation for whole system in \(T\) only
\(T = 20.6\) (N) or \(21\) (N)A1
Part (b)
AnswerMarks Guidance
WorkingMarks Notes
\(R - 1.5g = 1.5 \times 0.5\)M1 A1 Equation for brick only (1st alternative)
Force \(= 15.5\) (N) or \(15\) (N)A1
OR: \(T - R - 0.5g = 0.5 \times 0.5\)M1 A1 Scale pan only (2nd alternative); \(T\) does not need to be substituted
Force \(= 15.5\) (N) or \(15\) (N)A1 N.B. If \(R\) replaced by \(-R\), can score M1A1; second A1 only if candidate explains why negative sign ignored
## Question 2:

### Part (a)
| Working | Marks | Notes |
|---------|-------|-------|
| $T - 0.5g - 1.5g = 2 \times 0.5$ | M1 A1 | Equation for whole system in $T$ only |
| $T = 20.6$ (N) or $21$ (N) | A1 | |

### Part (b)
| Working | Marks | Notes |
|---------|-------|-------|
| $R - 1.5g = 1.5 \times 0.5$ | M1 A1 | Equation for brick only (1st alternative) |
| Force $= 15.5$ (N) or $15$ (N) | A1 | |
| **OR:** $T - R - 0.5g = 0.5 \times 0.5$ | M1 A1 | Scale pan only (2nd alternative); $T$ does not need to be substituted |
| Force $= 15.5$ (N) or $15$ (N) | A1 | N.B. If $R$ replaced by $-R$, can score M1A1; second A1 only if candidate explains why negative sign ignored |

---
2.

\begin{figure}[h]
\begin{center}
  \includegraphics[alt={},max width=\textwidth]{d408dd83-c5b2-4e55-b5c1-3e7f3faadbcb-04_327_255_283_847}
\captionsetup{labelformat=empty}
\caption{Figure 1}
\end{center}
\end{figure}

A vertical rope $A B$ has its end $B$ attached to the top of a scale pan. The scale pan has mass 0.5 kg and carries a brick of mass 1.5 kg , as shown in Figure 1. The scale pan is raised vertically upwards with constant acceleration $0.5 \mathrm {~m} \mathrm {~s} ^ { - 2 }$ using the rope $A B$. The rope is modelled as a light inextensible string.
\begin{enumerate}[label=(\alph*)]
\item Find the tension in the rope $A B$.
\item Find the magnitude of the force exerted on the scale pan by the brick.
\end{enumerate}

\hfill \mbox{\textit{Edexcel M1 2016 Q2 [6]}}