Edexcel M1 2007 June — Question 4 11 marks

Exam BoardEdexcel
ModuleM1 (Mechanics 1)
Year2007
SessionJune
Marks11
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicTravel graphs
TypeVelocity-time graph sketching
DifficultyModerate -0.8 This is a straightforward SUVAT problem requiring students to sketch a velocity-time graph and use the area-under-graph method to find unknown values. The multi-stage motion is clearly described, requiring only standard techniques (trapezium area formula and basic kinematics) with no conceptual challenges or novel problem-solving—easier than average for M1.
Spec3.02b Kinematic graphs: displacement-time and velocity-time3.02d Constant acceleration: SUVAT formulae

  1. A car is moving along a straight horizontal road. At time \(t = 0\), the car passes a point \(A\) with speed \(25 \mathrm {~m} \mathrm {~s} ^ { - 1 }\). The car moves with constant speed \(25 \mathrm {~m} \mathrm {~s} ^ { - 1 }\) until \(t = 10 \mathrm {~s}\). The car then decelerates uniformly for 8 s . At time \(t = 18 \mathrm {~s}\), the speed of the car is \(V \mathrm {~m} \mathrm {~s} ^ { - 1 }\) and this speed is maintained until the car reaches the point \(B\) at time \(t = 30 \mathrm {~s}\).
    1. Sketch, in the space below, a speed-time graph to show the motion of the car from \(A\) to \(B\).
    Given that \(A B = 526 \mathrm {~m}\), find
  2. the value of \(V\),
  3. the deceleration of the car between \(t = 10 \mathrm {~s}\) and \(t = 18 \mathrm {~s}\).

AnswerMarks Guidance
(a) 2 horizontal linesB1 (3 marks)
Joined by straight line sloping downB1
25, 10, 18, 30 or similarB1
(b) \(25 \times 10 + \frac{1}{2}(25 + V) \times 8 + 12 \times V = 526\)M1 A1 A1 (5 marks)
Solving to \(V = 11\)DM1 A1
(c) \(v = u + at\) ⟹ \(11 = 25 - 8a\)M1 A1ft (3 marks)
\(a = 1.75\) (ms⁻²)A1
[11]
**(a)** 2 horizontal lines | B1 | (3 marks)
Joined by straight line sloping down | B1 |
25, 10, 18, 30 or similar | B1 |

**(b)** $25 \times 10 + \frac{1}{2}(25 + V) \times 8 + 12 \times V = 526$ | M1 A1 A1 | (5 marks)
Solving to $V = 11$ | DM1 A1 |

**(c)** $v = u + at$ ⟹ $11 = 25 - 8a$ | M1 A1ft | (3 marks)
$a = 1.75$ (ms⁻²) | A1 |
| | [11] |
\begin{enumerate}
  \item A car is moving along a straight horizontal road. At time $t = 0$, the car passes a point $A$ with speed $25 \mathrm {~m} \mathrm {~s} ^ { - 1 }$. The car moves with constant speed $25 \mathrm {~m} \mathrm {~s} ^ { - 1 }$ until $t = 10 \mathrm {~s}$. The car then decelerates uniformly for 8 s . At time $t = 18 \mathrm {~s}$, the speed of the car is $V \mathrm {~m} \mathrm {~s} ^ { - 1 }$ and this speed is maintained until the car reaches the point $B$ at time $t = 30 \mathrm {~s}$.\\
(a) Sketch, in the space below, a speed-time graph to show the motion of the car from $A$ to $B$.
\end{enumerate}

Given that $A B = 526 \mathrm {~m}$, find\\
(b) the value of $V$,\\
(c) the deceleration of the car between $t = 10 \mathrm {~s}$ and $t = 18 \mathrm {~s}$.

\hfill \mbox{\textit{Edexcel M1 2007 Q4 [11]}}