CAIE P1 2017 November — Question 3 6 marks

Exam BoardCAIE
ModuleP1 (Pure Mathematics 1)
Year2017
SessionNovember
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicGeometric Sequences and Series
TypeRelationship between two GPs
DifficultyStandard +0.3 This question tests standard sum to infinity formula for GPs and sum of n terms for APs. Part (a) requires setting two GP sum formulas equal and solving algebraically—straightforward application with one constraint on r from convergence. Part (b) is similar but with AP formulas. Both parts are routine applications of memorized formulas with basic algebraic manipulation, slightly above average only due to the two-progression comparison setup.
Spec1.04h Arithmetic sequences: nth term and sum formulae1.04j Sum to infinity: convergent geometric series |r|<1

3
  1. A geometric progression has first term \(3 a\) and common ratio \(r\). A second geometric progression has first term \(a\) and common ratio \(- 2 r\). The two progressions have the same sum to infinity. Find the value of \(r\).
  2. The first two terms of an arithmetic progression are 15 and 19 respectively. The first two terms of a second arithmetic progression are 420 and 415 respectively. The two progressions have the same sum of the first \(n\) terms. Find the value of \(n\).

Question 3(i):
AnswerMarks Guidance
AnswerMarks Guidance
\(\frac{3a}{1-r} = \frac{a}{1+2r}\)M1 Attempt to equate 2 sums to infinity. At least one correct
\(3 + 6r = 1 - r\)DM1 Elimination of 1 variable (\(a\)) at any stage and multiplication
\(r = -\frac{2}{7}\)A1
Total: 3
Question 3(ii):
AnswerMarks Guidance
AnswerMarks Guidance
\(\frac{1}{2}n\big[2\times15+(n-1)4\big] = \frac{1}{2}n\big[2\times420+(n-1)(-5)\big]\)M1A1 Attempt to equate 2 sum to \(n\) terms, at least one correct (M1). Both correct (A1)
\(n = 91\)A1
Total: 3
## Question 3(i):

| Answer | Marks | Guidance |
|--------|-------|----------|
| $\frac{3a}{1-r} = \frac{a}{1+2r}$ | M1 | Attempt to equate 2 sums to infinity. At least one correct |
| $3 + 6r = 1 - r$ | DM1 | Elimination of 1 variable ($a$) at any stage and multiplication |
| $r = -\frac{2}{7}$ | A1 | |
| **Total: 3** | | |

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## Question 3(ii):

| Answer | Marks | Guidance |
|--------|-------|----------|
| $\frac{1}{2}n\big[2\times15+(n-1)4\big] = \frac{1}{2}n\big[2\times420+(n-1)(-5)\big]$ | M1A1 | Attempt to equate 2 sum to $n$ terms, at least one correct **(M1)**. Both correct **(A1)** |
| $n = 91$ | A1 | |
| **Total: 3** | | |

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3
\begin{enumerate}[label=(\alph*)]
\item A geometric progression has first term $3 a$ and common ratio $r$. A second geometric progression has first term $a$ and common ratio $- 2 r$. The two progressions have the same sum to infinity. Find the value of $r$.
\item The first two terms of an arithmetic progression are 15 and 19 respectively. The first two terms of a second arithmetic progression are 420 and 415 respectively. The two progressions have the same sum of the first $n$ terms. Find the value of $n$.
\end{enumerate}

\hfill \mbox{\textit{CAIE P1 2017 Q3 [6]}}