Edexcel FP2 2006 June — Question 3 12 marks

Exam BoardEdexcel
ModuleFP2 (Further Pure Mathematics 2)
Year2006
SessionJune
Marks12
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicModulus function
TypeSketch modulus functions involving quadratic or other non-linear
DifficultyStandard +0.3 This is a standard Further Pure modulus equation question requiring systematic case analysis (positive/negative cases), solving resulting quadratics, and checking solutions against constraints. While it involves multiple steps and a sketch, the techniques are routine for FP2 students with no novel insight required. Slightly easier than average A-level due to straightforward algebraic manipulation.
Spec1.02l Modulus function: notation, relations, equations and inequalities1.02p Interpret algebraic solutions: graphically1.02q Use intersection points: of graphs to solve equations1.02s Modulus graphs: sketch graph of |ax+b|1.02t Solve modulus equations: graphically with modulus function

3. (a) Use algebra to find the exact solutions of the equation $$\left| 2 x ^ { 2 } + x - 6 \right| = 6 - 3 x$$ (b) On the same diagram, sketch the curve with equation \(y = \left| 2 x ^ { 2 } + x - 6 \right|\) and the line with equation \(y = 6 - 3 x\).
(c) Find the set of values of \(x\) for which $$\left| 2 x ^ { 2 } + x - 6 \right| > 6 - 3 x$$ (3)(Total 12 marks)

AnswerMarks Guidance
(a) \(2x^2 + x - 6 = 6 - 3x\)M1 Rearranging to standard form
Leading to \(x^2 + 2x - 6 = 0\)M1 A1 Using surds required
\(-2x^2 - x + 6 = 6 - 3x\)M1
Leading to \(2x^2 - 2x = 0 \Rightarrow x = 0, 1\)A1 A1 6 marks total
(b) Accept if parts (a) and (b) done in reverse order
Curved shapeB1
LineB1
At least 3 intersectionsB1 3 marks total
(c) Using all 4 CVs and getting all into inequalitiesM1
\(x > \sqrt{7} - 1, x < -\sqrt{7} - 1\) bothA1 ft
fit their greatest positive and their least negative CVs
\(0 < x < 1\)A1 3 marks total [12]
**(a)** $2x^2 + x - 6 = 6 - 3x$ | M1 | Rearranging to standard form

Leading to $x^2 + 2x - 6 = 0$ | M1 A1 | Using surds required

$-2x^2 - x + 6 = 6 - 3x$ | M1 |

Leading to $2x^2 - 2x = 0 \Rightarrow x = 0, 1$ | A1 A1 | 6 marks total

**(b)** Accept if parts (a) and (b) done in reverse order | | 

Curved shape | B1 |

Line | B1 |

At least 3 intersections | B1 | 3 marks total

**(c)** Using all 4 CVs and getting all into inequalities | M1 |

$x > \sqrt{7} - 1, x < -\sqrt{7} - 1$ both | A1 ft |

fit their greatest positive and their least negative CVs | |

$0 < x < 1$ | A1 | 3 marks total [12]

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3. (a) Use algebra to find the exact solutions of the equation

$$\left| 2 x ^ { 2 } + x - 6 \right| = 6 - 3 x$$

(b) On the same diagram, sketch the curve with equation $y = \left| 2 x ^ { 2 } + x - 6 \right|$ and the line with equation $y = 6 - 3 x$.\\
(c) Find the set of values of $x$ for which

$$\left| 2 x ^ { 2 } + x - 6 \right| > 6 - 3 x$$

(3)(Total 12 marks)\\

\hfill \mbox{\textit{Edexcel FP2 2006 Q3 [12]}}