CAIE P1 2015 November — Question 2 4 marks

Exam BoardCAIE
ModuleP1 (Pure Mathematics 1)
Year2015
SessionNovember
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicBinomial Theorem (positive integer n)
TypeRatio of coefficients condition
DifficultyModerate -0.8 This is a straightforward binomial theorem application requiring students to write out two coefficient terms, set them equal, and solve for k. The algebra is simple (single variable, linear after simplification) and the method is a standard textbook exercise with no conceptual challenges beyond basic binomial coefficient recall.
Spec1.04a Binomial expansion: (a+b)^n for positive integer n

2 In the expansion of \(( x + 2 k ) ^ { 7 }\), where \(k\) is a non-zero constant, the coefficients of \(x ^ { 4 }\) and \(x ^ { 5 }\) are equal. Find the value of \(k\).

Question 2:
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\((x+2k)^7\), Term in \(x^5 = 21 \times 4k^2 = 84k^2\)B1
Term in \(x^4 = 35 \times 8k^3 = 280k^3\)B1
Equate and solve \(\rightarrow k = 0.3\) or \(\frac{3}{10}\)M1 A1 [4] Correct method to obtain \(k\)
## Question 2:

| Answer/Working | Marks | Guidance |
|---|---|---|
| $(x+2k)^7$, Term in $x^5 = 21 \times 4k^2 = 84k^2$ | **B1** | |
| Term in $x^4 = 35 \times 8k^3 = 280k^3$ | **B1** | |
| Equate and solve $\rightarrow k = 0.3$ or $\frac{3}{10}$ | **M1 A1** [4] | Correct method to obtain $k$ |

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2 In the expansion of $( x + 2 k ) ^ { 7 }$, where $k$ is a non-zero constant, the coefficients of $x ^ { 4 }$ and $x ^ { 5 }$ are equal. Find the value of $k$.

\hfill \mbox{\textit{CAIE P1 2015 Q2 [4]}}