CAIE P1 2015 November — Question 1 4 marks

Exam BoardCAIE
ModuleP1 (Pure Mathematics 1)
Year2015
SessionNovember
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicComposite & Inverse Functions
TypeSolve equation with inverses
DifficultyModerate -0.8 This question requires finding the inverse of a linear function and composing two linear functions, then solving a linear equation. All steps are routine algebraic manipulations with no conceptual challenges—standard P1 material requiring only direct application of well-practiced techniques.
Spec1.02v Inverse and composite functions: graphs and conditions for existence

1 Functions f and g are defined by $$\begin{aligned} & \mathrm { f } : x \mapsto 3 x + 2 , \quad x \in \mathbb { R } , \\ & \mathrm {~g} : x \mapsto 4 x - 12 , \quad x \in \mathbb { R } . \end{aligned}$$ Solve the equation \(\mathrm { f } ^ { - 1 } ( x ) = \operatorname { gf } ( x )\).

Question 1:
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(f: x \mapsto 3x+2\), \(g: x \mapsto 4x-12\)B1
\(f^{-1}(x) = \frac{x-2}{3}\)B1
\(gf(x) = 4(3x+2)-12\)M1 Equates, collects terms, +soln
Equate \(\rightarrow x = \frac{2}{7}\)A1 [4]
## Question 1:

| Answer/Working | Marks | Guidance |
|---|---|---|
| $f: x \mapsto 3x+2$, $g: x \mapsto 4x-12$ | **B1** | |
| $f^{-1}(x) = \frac{x-2}{3}$ | **B1** | |
| $gf(x) = 4(3x+2)-12$ | **M1** | Equates, collects terms, +soln |
| Equate $\rightarrow x = \frac{2}{7}$ | **A1** [4] | |

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1 Functions f and g are defined by

$$\begin{aligned}
& \mathrm { f } : x \mapsto 3 x + 2 , \quad x \in \mathbb { R } , \\
& \mathrm {~g} : x \mapsto 4 x - 12 , \quad x \in \mathbb { R } .
\end{aligned}$$

Solve the equation $\mathrm { f } ^ { - 1 } ( x ) = \operatorname { gf } ( x )$.

\hfill \mbox{\textit{CAIE P1 2015 Q1 [4]}}