Edexcel F1 2018 Specimen — Question 9 9 marks

Exam BoardEdexcel
ModuleF1 (Further Pure Mathematics 1)
Year2018
SessionSpecimen
Marks9
PaperDownload PDF ↗
TopicRoots of polynomials
TypeQuadratic with transformed roots
DifficultyStandard +0.8 This is a Further Maths question requiring systematic application of Vieta's formulas and algebraic manipulation to find sums/products of transformed roots. Part (a) uses standard identities (α²+β² and α³+β³), while part (b) requires finding sum and product of (α²+β) and (β²+α), which demands careful algebraic work but follows established techniques. More challenging than typical A-level questions due to the multi-step reasoning and algebraic complexity, but still a standard Further Maths exercise.
Spec4.05a Roots and coefficients: symmetric functions4.05b Transform equations: substitution for new roots

  1. The quadratic equation
$$2 x ^ { 2 } + 4 x - 3 = 0$$ has roots \(\alpha\) and \(\beta\).
Without solving the quadratic equation,
  1. find the exact value of
    1. \(\alpha ^ { 2 } + \beta ^ { 2 }\)
    2. \(\alpha ^ { 3 } + \beta ^ { 3 }\)
  2. Find a quadratic equation which has roots ( \(\alpha ^ { 2 } + \beta\) ) and ( \(\beta ^ { 2 } + \alpha\) ), giving your answer in the form \(a x ^ { 2 } + b x + c = 0\), where \(a , b\) and \(c\) are integers.
    VIAV SIHI NI BIIIM ION OCVGHV SIHI NI GHIYM ION OCVJ4V SIHI NI JIIYM ION OC

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  \item The quadratic equation
\end{enumerate}

$$2 x ^ { 2 } + 4 x - 3 = 0$$

has roots $\alpha$ and $\beta$.\\
Without solving the quadratic equation,\\
(a) find the exact value of\\
(i) $\alpha ^ { 2 } + \beta ^ { 2 }$\\
(ii) $\alpha ^ { 3 } + \beta ^ { 3 }$\\
(b) Find a quadratic equation which has roots ( $\alpha ^ { 2 } + \beta$ ) and ( $\beta ^ { 2 } + \alpha$ ), giving your answer in the form $a x ^ { 2 } + b x + c = 0$, where $a , b$ and $c$ are integers.

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VIAV SIHI NI BIIIM ION OC & VGHV SIHI NI GHIYM ION OC & VJ4V SIHI NI JIIYM ION OC \\
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\hfill \mbox{\textit{Edexcel F1 2018 Q9 [9]}}