Edexcel F1 2018 Specimen — Question 4 5 marks

Exam BoardEdexcel
ModuleF1 (Further Pure Mathematics 1)
Year2018
SessionSpecimen
Marks5
PaperDownload PDF ↗
TopicMatrices
TypeNon-singular matrix proof
DifficultyModerate -0.5 This is a straightforward Further Maths question requiring standard techniques: computing a 2×2 determinant, completing the square to show it's always positive, and applying the formula for 2×2 matrix inverse. While it's Further Maths content (making it harder than basic A-level), the methods are routine and mechanical with no problem-solving insight needed, placing it slightly below average difficulty overall.
Spec4.03h Determinant 2x2: calculation4.03n Inverse 2x2 matrix4.03o Inverse 3x3 matrix

  1. Given that
$$\mathbf { A } = \left( \begin{array} { c c } k & 3 \\ - 1 & k + 2 \end{array} \right) \text {, where } k \text { is a constant }$$
  1. show that \(\operatorname { det } ( \mathbf { A } ) > 0\) for all real values of \(k\),
  2. find \(\mathbf { A } ^ { - 1 }\) in terms of \(k\).

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  \item Given that
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$$\mathbf { A } = \left( \begin{array} { c c } 
k & 3 \\
- 1 & k + 2
\end{array} \right) \text {, where } k \text { is a constant }$$

(a) show that $\operatorname { det } ( \mathbf { A } ) > 0$ for all real values of $k$,\\
(b) find $\mathbf { A } ^ { - 1 }$ in terms of $k$.\\

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\hfill \mbox{\textit{Edexcel F1 2018 Q4 [5]}}