Edexcel F1 2018 January — Question 8 11 marks

Exam BoardEdexcel
ModuleF1 (Further Pure Mathematics 1)
Year2018
SessionJanuary
Marks11
PaperDownload PDF ↗
TopicProof by induction
TypeProve recurrence relation formula
DifficultyStandard +0.3 This is a standard two-part induction question from Further Pure 1. Part (i) involves proving a recurrence relation formula using straightforward algebraic manipulation, while part (ii) is a divisibility proof requiring modular arithmetic. Both are textbook-style exercises with well-established techniques, making this slightly easier than average for Further Maths students but appropriately challenging for the syllabus.
Spec4.01a Mathematical induction: construct proofs

8. (i) A sequence of numbers is defined by $$\begin{aligned} u _ { 1 } & = 3 \\ u _ { n + 1 } & = u _ { n } + 3 n - 2 \quad n \geqslant 1 \end{aligned}$$ Prove by induction that, for all positive integers \(n\), $$u _ { n } = \frac { 3 } { 2 } n ^ { 2 } - \frac { 7 } { 2 } n + 5$$ (ii) Prove by induction that, for all positive integers \(n\), $$f ( n ) = 3 ^ { 2 n + 3 } + 40 n - 27 \text { is divisible by } 64$$
\includegraphics[max width=\textwidth, alt={}]{ced97dcd-7998-4c0f-9285-3fe03b7a659b-32_2632_1828_121_121}

8. (i) A sequence of numbers is defined by

$$\begin{aligned}
u _ { 1 } & = 3 \\
u _ { n + 1 } & = u _ { n } + 3 n - 2 \quad n \geqslant 1
\end{aligned}$$

Prove by induction that, for all positive integers $n$,

$$u _ { n } = \frac { 3 } { 2 } n ^ { 2 } - \frac { 7 } { 2 } n + 5$$

(ii) Prove by induction that, for all positive integers $n$,

$$f ( n ) = 3 ^ { 2 n + 3 } + 40 n - 27 \text { is divisible by } 64$$

\begin{center}

\end{center}

\begin{center}
\includegraphics[max width=\textwidth, alt={}]{ced97dcd-7998-4c0f-9285-3fe03b7a659b-32_2632_1828_121_121}
\end{center}

\hfill \mbox{\textit{Edexcel F1 2018 Q8 [11]}}