Edexcel C4 2006 June — Question 1 7 marks

Exam BoardEdexcel
ModuleC4 (Core Mathematics 4)
Year2006
SessionJune
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicImplicit equations and differentiation
TypeFind normal equation at point
DifficultyModerate -0.3 This is a straightforward implicit differentiation question requiring students to differentiate term-by-term, substitute a given point to find the gradient, then find the perpendicular normal. All steps are routine C4 techniques with no conceptual challenges, making it slightly easier than average.
Spec1.07m Tangents and normals: gradient and equations1.07s Parametric and implicit differentiation

  1. A curve \(C\) is described by the equation
$$3 x ^ { 2 } - 2 y ^ { 2 } + 2 x - 3 y + 5 = 0$$ Find an equation of the normal to \(C\) at the point ( 0,1 ), giving your answer in the form \(a x + b y + c = 0\), where \(a , b\) and \(c\) are integers.

\begin{enumerate}
  \item A curve $C$ is described by the equation
\end{enumerate}

$$3 x ^ { 2 } - 2 y ^ { 2 } + 2 x - 3 y + 5 = 0$$

Find an equation of the normal to $C$ at the point ( 0,1 ), giving your answer in the form $a x + b y + c = 0$, where $a , b$ and $c$ are integers.\\

\hfill \mbox{\textit{Edexcel C4 2006 Q1 [7]}}