One unknown constant: find it then solve

Polynomial has one unknown constant; find it using the given factor, then solve f(x) = 0.

5 questions · Moderate -0.7

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CAIE P2 2004 June Q3
6 marks Moderate -0.8
3 The cubic polynomial \(2 x ^ { 3 } + a x ^ { 2 } - 13 x - 6\) is denoted by \(\mathrm { f } ( x )\). It is given that ( \(x - 3\) ) is a factor of \(\mathrm { f } ( x )\).
  1. Find the value of \(a\).
  2. When \(a\) has this value, solve the equation \(\mathrm { f } ( x ) = 0\).
CAIE P2 2006 November Q3
6 marks Moderate -0.8
3 The polynomial \(4 x ^ { 3 } - 7 x + a\), where \(a\) is a constant, is denoted by \(\mathrm { p } ( x )\). It is given that ( \(2 x - 3\) ) is a factor of \(\mathrm { p } ( x )\).
  1. Show that \(a = - 3\).
  2. Hence, or otherwise, solve the equation \(\mathrm { p } ( x ) = 0\).
CAIE P2 2007 November Q5
6 marks Moderate -0.8
5 The polynomial \(3 x ^ { 3 } + 8 x ^ { 2 } + a x - 2\), where \(a\) is a constant, is denoted by \(\mathrm { p } ( x )\). It is given that \(( x + 2 )\) is a factor of \(\mathrm { p } ( x )\).
  1. Find the value of \(a\).
  2. When \(a\) has this value, solve the equation \(\mathrm { p } ( x ) = 0\).
Edexcel C2 Q2
6 marks Moderate -0.8
2. $$f ( x ) = x ^ { 3 } + k x - 20 .$$ Given that \(\mathrm { f } ( x )\) is exactly divisible by ( \(x + 1\) ),
  1. find the value of the constant \(k\),
  2. solve the equation \(\mathrm { f } ( x ) = 0\).
OCR C2 Q2
6 marks Moderate -0.3
$$f(x) = x^3 + kx - 20.$$ Given that f(x) is exactly divisible by \((x + 1)\),
  1. find the value of the constant \(k\), [2]
  2. solve the equation \(f(x) = 0\). [4]