A curve is such that \(\frac{dy}{dx} = \frac{2}{a}x^{-\frac{1}{2}} + ax^{-\frac{3}{2}}\), where \(a\) is a positive constant. The point \(A(a^2, 3)\) lies on the curve. Find, in terms of \(a\),
- the equation of the tangent to the curve at \(A\), simplifying your answer, [3]
- the equation of the curve. [4]
It is now given that \(B(16, 8)\) also lies on the curve.
- Find the value of \(a\) and, using this value, find the distance \(AB\). [5]