Region bounded by two curves

4 The diagram shows a sketch of the curves with equations \(y = 2 x ^ { \frac { 3 } { 2 } }\) and \(y = 8 x ^ { \frac { 1 } { 2 } }\). \includegraphics[max width=\textwidth, alt={}, center]{0e19665b-5ee5-49e4-8de2-6c8dd17f61eb-3_433_720_1452_644} The curves intersect at the origin and at the point \(A\), where \(x = 4\).

1. 1. For the curve \(y = 2 x ^ { \frac { 3 } { 2 } }\), find the value of \(\frac { \mathrm { d } y } { \mathrm {~d} x }\) when \(x = 4\).
      (2 marks)
   2. Find an equation of the normal to the curve \(y = 2 x ^ { \frac { 3 } { 2 } }\) at the point \(A\).
2. 1. Find \(\int 8 x ^ { \frac { 1 } { 2 } } \mathrm {~d} x\).
   2. Find the area of the shaded region bounded by the two curves.
3. Describe a single geometrical transformation that maps the graph of \(y = 2 x ^ { \frac { 3 } { 2 } }\) onto the graph of \(y = 2 ( x + 3 ) ^ { \frac { 3 } { 2 } }\).
   (2 marks)

14. The diagram below shows a sketch of the curve \(C\) with equation \(y = 2 - 3 x - 2 x ^ { 2 }\) and the line \(L\) with equation \(y = x + 2\). The curve and the line intersect the coordinate axes at the points \(A\) and \(B\). \includegraphics[max width=\textwidth, alt={}, center]{9bb29d6e-2dbb-4212-b3e0-45e7b12c0c43-18_775_970_589_543}

1. Write down the coordinates of \(A\) and \(B\).
   

   (b) Calculate the area enclosed by \(C\) and \(L\). [6]

   Examiner only

14 In this question you must show detailed reasoning. Fig. 14 shows the graphs of \(y = \sin x \cos 2 x\) and \(y = \frac { 1 } { 2 } - \sin 2 x \cos x\). \begin{figure}[h] \end{figure} Use integration to find the area between the two curves, giving your answer in an exact form.