Vertical collision or projection

Particles moving vertically collide in mid-air, or one is projected upward and collides with another; use conservation of momentum and kinematics under gravity.

2 questions · Standard +0.4

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CAIE M1 2021 June Q6
8 marks Challenging +1.2
6 A particle \(A\) is projected vertically upwards from level ground with an initial speed of \(30 \mathrm {~m} \mathrm {~s} ^ { - 1 }\). At the same instant a particle \(B\) is released from rest 15 m vertically above \(A\). The mass of one of the particles is twice the mass of the other particle. During the subsequent motion \(A\) and \(B\) collide and coalesce to form particle \(C\). Find the difference between the two possible times at which \(C\) hits the ground.
\(7 \quad\) A particle \(P\) moving in a straight line starts from rest at a point \(O\) and comes to rest 16 s later. At time \(t \mathrm {~s}\) after leaving \(O\), the acceleration \(a \mathrm {~m} \mathrm {~s} ^ { - 2 }\) of \(P\) is given by $$\begin{array} { l l } a = 6 + 4 t & 0 \leqslant t < 2 , \\ a = 14 & 2 \leqslant t < 4 , \\ a = 16 - 2 t & 4 \leqslant t \leqslant 16 . \end{array}$$ There is no sudden change in velocity at any instant.
  1. Find the values of \(t\) when the velocity of \(P\) is \(55 \mathrm {~m} \mathrm {~s} ^ { - 1 }\).
  2. Complete the sketch of the velocity-time diagram.
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  3. Find the distance travelled by \(P\) when it is decelerating.
    If you use the following lined page to complete the answer(s) to any question(s), the question number(s) must be clearly shown.
CAIE M1 2023 November Q5
8 marks Moderate -0.3
5 A particle \(A\) of mass 0.5 kg is projected vertically upwards from horizontal ground with speed \(25 \mathrm {~m} \mathrm {~s} ^ { - 1 }\).
  1. Find the speed of \(A\) when it reaches a height of 20 m above the ground.
    When \(A\) reaches a height of 20 m , it collides with a particle \(B\) of mass 0.3 kg which is moving downwards in the same vertical line as \(A\) with speed \(32.5 \mathrm {~ms} ^ { - 1 }\). In the collision between the two particles, \(B\) is brought to instantaneous rest.
  2. Show that the velocity of \(A\) immediately after the collision is \(4.5 \mathrm {~m} \mathrm {~s} ^ { - 1 }\) downwards.
  3. Find the time interval between \(A\) and \(B\) reaching the ground. You should assume that \(A\) does not bounce when it reaches the ground.