Given that \(\frac{z + 2i}{z - \lambda i} = i\), where \(\lambda\) is a positive, real constant,
- show that \(z = \left( \frac{\lambda}{2} + 1 \right) + i \left( \frac{\lambda}{2} - 1 \right)\). [5]
Given also that \(\arg z = \arctan \frac{1}{3}\), calculate
- the value of \(\lambda\), [3]
- the value of \(|z|^2\). [2]