\includegraphics{figure_2}
Figure 2 shows part of the curve \(C\) with equation
$$y = (x - 1)(x^2 - 4).$$
The curve cuts the \(x\)-axis at the points \(P\), \((1, 0)\) and \(Q\), as shown in Figure 2.
- Write down the \(x\)-coordinate of \(P\) and the \(x\)-coordinate of \(Q\). [2]
- Show that \(\frac{dy}{dx} = 3x^2 - 2x - 4\). [3]
- Show that \(y = x + 7\) is an equation of the tangent to \(C\) at the point \((-1, 6)\). [2]
The tangent to \(C\) at the point \(R\) is parallel to the tangent at the point \((-1, 6)\).
- Find the exact coordinates of \(R\). [5]