\includegraphics{figure_4}
A small ball is projected from a fixed point \(O\) so as to hit a target \(T\) which is at a horizontal distance \(9a\) from \(O\) and at a height \(6a\) above the level of \(O\). The ball is projected with speed \(\sqrt{(27ag)}\) at an angle \(\theta\) to the horizontal, as shown in Figure 4. The ball is modelled as a particle moving freely under gravity.
- Show that tan\(^2 \theta - 6\) tan \(\theta + 5 = 0\) [7]
The two possible angles of projection are \(\theta_1\) and \(\theta_2\), where \(\theta_1 > \theta_2\).
- Find tan \(\theta_1\) and tan \(\theta_2\). [3]
The particle is projected at the larger angle \(\theta_1\).
- Show that the time of flight from \(O\) to \(T\) is \(\sqrt{\left(\frac{78a}{g}\right)}\). [3]
- Find the speed of the particle immediately before it hits \(T\). [3]