CAIE P1 2013 November — Question 7 8 marks

Exam BoardCAIE
ModuleP1 (Pure Mathematics 1)
Year2013
SessionNovember
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicArithmetic Sequences and Series
TypeReal-world AP: find term or total
DifficultyModerate -0.8 This question tests standard arithmetic sequence formulas (finding nth term and sum) and basic geometric progression (finding first term and sum to infinity). Part (a) requires straightforward application of a_n = a_1 + (n-1)d with simple arithmetic, while part (b) involves routine GP formulas. Both parts are textbook exercises requiring only direct formula application with no problem-solving insight or complex manipulation.
Spec1.04h Arithmetic sequences: nth term and sum formulae1.04i Geometric sequences: nth term and finite series sum1.04j Sum to infinity: convergent geometric series |r|<1

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  1. An athlete runs the first mile of a marathon in 5 minutes. His speed reduces in such a way that each mile takes 12 seconds longer than the preceding mile.
    1. Given that the \(n\)th mile takes 9 minutes, find the value of \(n\).
    2. Assuming that the length of the marathon is 26 miles, find the total time, in hours and minutes, to complete the marathon.
  2. The second and third terms of a geometric progression are 48 and 32 respectively. Find the sum to infinity of the progression.

AnswerMarks Guidance
(a) (i) \(a = 300\), \(d = 12\) \(\to 540 = 300 + (n-1)12 \to n = 21\)M1 A1 [2] Use of nth term. Ans 20 gets 0. Ignore incorrect units. Correct use of \(s_n\) formula.
(ii) \(S_{26} = 13(600 + 25 \times 12) = 11700 \to 3\) hours 15 minutes.M1, A1 [2] Correct use of \(s_n\) formula.
(b) \(ar = 48\) and \(ar^2 = 32 \to r = \frac{3}{4} \to a = 72\). \(S_\infty = 72 \div \frac{1}{3} = 216\).M1, A1, M1, A1✓ [4] Needs \(ar\) and \(ar^2\) + attempt at \(a\) and \(r\). Correct \(S_\infty\) formula with \(
(a) (i) $a = 300$, $d = 12$ $\to 540 = 300 + (n-1)12 \to n = 21$ | M1 A1 [2] | Use of nth term. Ans 20 gets 0. Ignore incorrect units. Correct use of $s_n$ formula.

(ii) $S_{26} = 13(600 + 25 \times 12) = 11700 \to 3$ hours 15 minutes. | M1, A1 [2] | Correct use of $s_n$ formula.

(b) $ar = 48$ and $ar^2 = 32 \to r = \frac{3}{4} \to a = 72$. $S_\infty = 72 \div \frac{1}{3} = 216$. | M1, A1, M1, A1✓ [4] | Needs $ar$ and $ar^2$ + attempt at $a$ and $r$. Correct $S_\infty$ formula with $|r| < 1$.
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\begin{enumerate}[label=(\alph*)]
\item An athlete runs the first mile of a marathon in 5 minutes. His speed reduces in such a way that each mile takes 12 seconds longer than the preceding mile.
\begin{enumerate}[label=(\roman*)]
\item Given that the $n$th mile takes 9 minutes, find the value of $n$.
\item Assuming that the length of the marathon is 26 miles, find the total time, in hours and minutes, to complete the marathon.
\end{enumerate}\item The second and third terms of a geometric progression are 48 and 32 respectively. Find the sum to infinity of the progression.
\end{enumerate}

\hfill \mbox{\textit{CAIE P1 2013 Q7 [8]}}