Edexcel C3 2012 June — Question 7 11 marks

Exam BoardEdexcel
ModuleC3 (Core Mathematics 3)
Year2012
SessionJune
Marks11
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicProduct & Quotient Rules
TypeFind derivative of quotient
DifficultyModerate -0.3 This is a straightforward multi-part differentiation question testing standard product rule, quotient rule, and implicit differentiation techniques. Part (a)(i) is routine product rule with basic functions, (a)(ii) requires quotient rule and algebraic simplification, and part (b) involves chain rule with inverse trig. All are textbook-standard applications with no novel problem-solving required, making it slightly easier than average.
Spec1.07l Derivative of ln(x): and related functions1.07q Product and quotient rules: differentiation1.07r Chain rule: dy/dx = dy/du * du/dx and connected rates1.07s Parametric and implicit differentiation

  1. Differentiate with respect to \(x\),
    1. \(x ^ { \frac { 1 } { 2 } } \ln ( 3 x )\)
    2. \(\frac { 1 - 10 x } { ( 2 x - 1 ) ^ { 5 } }\), giving your answer in its simplest form.
  2. Given that \(x = 3 \tan 2 y\) find \(\frac { \mathrm { d } y } { \mathrm {~d} x }\) in terms of \(x\).

AnswerMarks Guidance
(a)(i) \(\frac{d}{dx}(\ln(3x)) = \frac{3}{3x}\)M1 Attempts to differentiate \(\ln(3x)\) to \(\frac{B}{x}\). Note that \(\frac{1}{3x}\) is fine.
\(\frac{d}{dx}(x^2 \ln(3x)) = \ln(3x) \times \frac{1}{2} x^{-\frac{1}{2}} + x^2 \times \frac{1}{3x}\)M1A1 Attempts the product rule for \(x^{\frac{1}{2}} \ln(3x)\). If the rule is quoted it must be correct. There must have been some attempt to differentiate both terms. If the rule is not quoted nor implied from their stating of
| (a)(i) $\frac{d}{dx}(\ln(3x)) = \frac{3}{3x}$ | M1 | Attempts to differentiate $\ln(3x)$ to $\frac{B}{x}$. Note that $\frac{1}{3x}$ is fine. |
|---|---|---|
| $\frac{d}{dx}(x^2 \ln(3x)) = \ln(3x) \times \frac{1}{2} x^{-\frac{1}{2}} + x^2 \times \frac{1}{3x}$ | M1A1 | Attempts the product rule for $x^{\frac{1}{2}} \ln(3x)$. If the rule is quoted it must be correct. There must have been some attempt to differentiate both terms. If the rule is not quoted nor implied from their stating of
\begin{enumerate}[label=(\alph*)]
\item Differentiate with respect to $x$,
\begin{enumerate}[label=(\roman*)]
\item $x ^ { \frac { 1 } { 2 } } \ln ( 3 x )$
\item $\frac { 1 - 10 x } { ( 2 x - 1 ) ^ { 5 } }$, giving your answer in its simplest form.
\end{enumerate}\item Given that $x = 3 \tan 2 y$ find $\frac { \mathrm { d } y } { \mathrm {~d} x }$ in terms of $x$.
\end{enumerate}

\hfill \mbox{\textit{Edexcel C3 2012 Q7 [11]}}