Edexcel C3 2011 June — Question 4 8 marks

Exam BoardEdexcel
ModuleC3 (Core Mathematics 3)
Year2011
SessionJune
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicComposite & Inverse Functions
TypeFind inverse function
DifficultyModerate -0.3 This is a standard C3 inverse function question with routine techniques: finding inverse by swapping x and y, determining domain/range, and composing functions. Part (a) requires basic logarithm manipulation, (b) is straightforward range-to-domain conversion, (c) involves direct substitution that simplifies nicely, and (d) requires recognizing that e^(x²) ≥ 1. All parts use well-practiced methods with no novel problem-solving required, making it slightly easier than average.
Spec1.02u Functions: definition and vocabulary (domain, range, mapping)1.02v Inverse and composite functions: graphs and conditions for existence1.06a Exponential function: a^x and e^x graphs and properties1.06d Natural logarithm: ln(x) function and properties

4. The function \(f\) is defined by $$\mathrm { f } : x \mapsto 4 - \ln ( x + 2 ) , \quad x \in \mathbb { R } , x \geqslant - 1$$
  1. Find \(\mathrm { f } ^ { - 1 } ( x )\).
  2. Find the domain of \(\mathrm { f } ^ { - 1 }\). The function \(g\) is defined by $$\mathrm { g } : x \mapsto \mathrm { e } ^ { x ^ { 2 } } - 2 , \quad x \in \mathbb { R }$$
  3. Find \(\mathrm { fg } ( x )\), giving your answer in its simplest form.
  4. Find the range of fg.

Question 4:
Part (a)
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(y = 4 - \ln(x+2)\), \(\ln(x+2) = 4-y\), \(x+2 = e^{4-y}\)M1
\(x = e^{4-y} - 2\), so \(f^{-1}(x) = e^{4-x} - 2\)M1A1 oe
(3)
Part (b)
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(x \leq 4\)B1
(1)
Part (c)
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(fg(x) = 4 - \ln(e^{x^2} - 2 + 2)\)M1
\(fg(x) = 4 - x^2\)dM1A1
(3)
Part (d)
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(fg(x) \leq 4\)B1ft
(1)8 Marks
# Question 4:

## Part (a)
| Answer/Working | Marks | Guidance |
|---|---|---|
| $y = 4 - \ln(x+2)$, $\ln(x+2) = 4-y$, $x+2 = e^{4-y}$ | M1 | |
| $x = e^{4-y} - 2$, so $f^{-1}(x) = e^{4-x} - 2$ | M1A1 | oe |
| | (3) | |

## Part (b)
| Answer/Working | Marks | Guidance |
|---|---|---|
| $x \leq 4$ | B1 | |
| | (1) | |

## Part (c)
| Answer/Working | Marks | Guidance |
|---|---|---|
| $fg(x) = 4 - \ln(e^{x^2} - 2 + 2)$ | M1 | |
| $fg(x) = 4 - x^2$ | dM1A1 | |
| | (3) | |

## Part (d)
| Answer/Working | Marks | Guidance |
|---|---|---|
| $fg(x) \leq 4$ | B1ft | |
| | (1) | **8 Marks** |

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4. The function $f$ is defined by

$$\mathrm { f } : x \mapsto 4 - \ln ( x + 2 ) , \quad x \in \mathbb { R } , x \geqslant - 1$$
\begin{enumerate}[label=(\alph*)]
\item Find $\mathrm { f } ^ { - 1 } ( x )$.
\item Find the domain of $\mathrm { f } ^ { - 1 }$.

The function $g$ is defined by

$$\mathrm { g } : x \mapsto \mathrm { e } ^ { x ^ { 2 } } - 2 , \quad x \in \mathbb { R }$$
\item Find $\mathrm { fg } ( x )$, giving your answer in its simplest form.
\item Find the range of fg.
\end{enumerate}

\hfill \mbox{\textit{Edexcel C3 2011 Q4 [8]}}