Edexcel P3 2024 June — Question 4 9 marks

Exam BoardEdexcel
ModuleP3 (Pure Mathematics 3)
Year2024
SessionJune
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicHarmonic Form
TypeFind maximum or minimum value
DifficultyStandard +0.3 This is a standard P3/C3 harmonic form question following a well-established template: use double angle identities, convert to R sin(θ+α) form, then find maximum and corresponding x-value. All steps are routine applications of learned techniques with no novel problem-solving required, making it slightly easier than average.
Spec1.05l Double angle formulae: and compound angle formulae1.05n Harmonic form: a sin(x)+b cos(x) = R sin(x+alpha) etc1.05o Trigonometric equations: solve in given intervals

4. $$f ( x ) = 8 \sin x \cos x + 4 \cos ^ { 2 } x - 3$$
  1. Write \(\mathrm { f } ( x )\) in the form $$a \sin 2 x + b \cos 2 x + c$$ where \(a\), \(b\) and \(c\) are integers to be found.
  2. Use the answer to part (a) to write \(\mathrm { f } ( x )\) in the form $$R \sin ( 2 x + \alpha ) + c$$ where \(R > 0\) and \(0 < \alpha < \frac { \pi } { 2 }\) Give the exact value of \(R\) and give the value of \(\alpha\) in radians to 3 significant figures.
  3. Hence, or otherwise,
    1. state the maximum value of \(\mathrm { f } ( x )\)
    2. find the second smallest positive value of \(x\) at which a maximum value of \(\mathrm { f } ( x )\) occurs. Give your answer to 3 significant figures.

Question 4:
Part (a):
AnswerMarks Guidance
Answer/WorkingMark Guidance
States or uses \(\sin 2x = 2\sin x\cos x\) or \(\cos 2x = \pm2\cos^2 x \pm 1\)M1 Either identity stated; can be implied by \(a=4\), or \(b=\pm2\) and \(c=-5\) or \(-1\)
Uses both \(\sin 2x = 2\sin x\cos x\) and \(\cos 2x = \pm2\cos^2 x \pm 1\) in \(f(x)\)dM1 Produces form \(a\sin 2x + b\cos 2x + c\); condone slips when substituting
\(f(x) = 4\sin 2x + 2\cos 2x - 1\)A1 Correct answer; must be in terms of \(x\)
Part (b):
AnswerMarks Guidance
Answer/WorkingMark Guidance
\(R^2 = a^2 + b^2 \Rightarrow R = \sqrt{20}\) or \(2\sqrt{5}\)B1ft Follow through on their \(a\) or \(b\); can be implied by correct exact value
\(\tan\alpha = \frac{b}{a} \Rightarrow \alpha = \ldots\) (= awrt 0.464)M1 Uses correct method with their \(a\) and \(b\); allow degrees: \(\alpha=\) awrt \(26.6°\)
\(f(x) = 2\sqrt{5}\sin(2x + 0.464) - 1\)A1 Full marks only if correct \(a\), \(b\), \(c\) found in (a)
Part (c)(i):
AnswerMarks Guidance
Answer/WorkingMark Guidance
Maximum value \(= 2\sqrt{5} - 1\)B1ft e.g. \(\sqrt{20}-1\); follow through on \(R+c\) as long as \(R\) correctly found; \(c\) cannot be 0
Part (c)(ii):
AnswerMarks Guidance
Answer/WorkingMark Guidance
Solves \(2x + \alpha = \frac{5\pi}{2} \Rightarrow x = \ldots\)M1 Using their \(\alpha\) from (b); \(\frac{5\pi}{2} = 7.85\ldots\) may be used
\(x =\) awrt \(3.69\) (or \(x =\) awrt \(3.70\))A1 If several angles found, must indicate final answer
# Question 4:

## Part (a):

| Answer/Working | Mark | Guidance |
|---|---|---|
| States or uses $\sin 2x = 2\sin x\cos x$ or $\cos 2x = \pm2\cos^2 x \pm 1$ | M1 | Either identity stated; can be implied by $a=4$, or $b=\pm2$ and $c=-5$ or $-1$ |
| Uses both $\sin 2x = 2\sin x\cos x$ and $\cos 2x = \pm2\cos^2 x \pm 1$ in $f(x)$ | dM1 | Produces form $a\sin 2x + b\cos 2x + c$; condone slips when substituting |
| $f(x) = 4\sin 2x + 2\cos 2x - 1$ | A1 | Correct answer; must be in terms of $x$ |

## Part (b):

| Answer/Working | Mark | Guidance |
|---|---|---|
| $R^2 = a^2 + b^2 \Rightarrow R = \sqrt{20}$ or $2\sqrt{5}$ | B1ft | Follow through on their $a$ or $b$; can be implied by correct exact value |
| $\tan\alpha = \frac{b}{a} \Rightarrow \alpha = \ldots$ (= awrt 0.464) | M1 | Uses correct method with their $a$ and $b$; allow degrees: $\alpha=$ awrt $26.6°$ |
| $f(x) = 2\sqrt{5}\sin(2x + 0.464) - 1$ | A1 | Full marks only if correct $a$, $b$, $c$ found in (a) |

## Part (c)(i):

| Answer/Working | Mark | Guidance |
|---|---|---|
| Maximum value $= 2\sqrt{5} - 1$ | B1ft | e.g. $\sqrt{20}-1$; follow through on $R+c$ as long as $R$ correctly found; $c$ cannot be 0 |

## Part (c)(ii):

| Answer/Working | Mark | Guidance |
|---|---|---|
| Solves $2x + \alpha = \frac{5\pi}{2} \Rightarrow x = \ldots$ | M1 | Using their $\alpha$ from (b); $\frac{5\pi}{2} = 7.85\ldots$ may be used |
| $x =$ awrt $3.69$ (or $x =$ awrt $3.70$) | A1 | If several angles found, must indicate final answer |

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4.

$$f ( x ) = 8 \sin x \cos x + 4 \cos ^ { 2 } x - 3$$
\begin{enumerate}[label=(\alph*)]
\item Write $\mathrm { f } ( x )$ in the form

$$a \sin 2 x + b \cos 2 x + c$$

where $a$, $b$ and $c$ are integers to be found.
\item Use the answer to part (a) to write $\mathrm { f } ( x )$ in the form

$$R \sin ( 2 x + \alpha ) + c$$

where $R > 0$ and $0 < \alpha < \frac { \pi } { 2 }$\\
Give the exact value of $R$ and give the value of $\alpha$ in radians to 3 significant figures.
\item Hence, or otherwise,
\begin{enumerate}[label=(\roman*)]
\item state the maximum value of $\mathrm { f } ( x )$
\item find the second smallest positive value of $x$ at which a maximum value of $\mathrm { f } ( x )$ occurs. Give your answer to 3 significant figures.
\end{enumerate}\end{enumerate}

\hfill \mbox{\textit{Edexcel P3 2024 Q4 [9]}}