CAIE P1 2011 November — Question 2 3 marks

Exam BoardCAIE
ModuleP1 (Pure Mathematics 1)
Year2011
SessionNovember
Marks3
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicStationary points and optimisation
TypeProve or show increasing/decreasing function
DifficultyModerate -0.8 This is a straightforward differentiation question requiring students to find dy/dx = 9x² - 12x + 4, then show it's always non-negative by completing the square or using the discriminant. It's a standard technique with clear method and minimal steps, making it easier than average but not trivial since it requires recognizing how to prove non-negativity of a quadratic.
Spec1.07i Differentiate x^n: for rational n and sums1.07o Increasing/decreasing: functions using sign of dy/dx

2 A curve has equation \(y = 3 x ^ { 3 } - 6 x ^ { 2 } + 4 x + 2\). Show that the gradient of the curve is never negative.

Question 2:
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(\frac{\delta y}{\delta x} = 9x^2 - 12x + 4\)M1A1
\((3x-2)^2 \geq 0\)A1 [3]
## Question 2:

| Answer/Working | Marks | Guidance |
|---|---|---|
| $\frac{\delta y}{\delta x} = 9x^2 - 12x + 4$ | M1A1 | |
| $(3x-2)^2 \geq 0$ | A1 | [3] |

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2 A curve has equation $y = 3 x ^ { 3 } - 6 x ^ { 2 } + 4 x + 2$. Show that the gradient of the curve is never negative.

\hfill \mbox{\textit{CAIE P1 2011 Q2 [3]}}