4. (a) Show that the equation $$3 \sin ^ { 2 } \theta - 2 \cos ^ { 2 } \theta = 1$$ can be written as $$5 \sin ^ { 2 } \theta = 3$$ (b) Hence solve, for \(0 ^ { \circ } \leqslant \theta < 360 ^ { \circ }\), the equation $$3 \sin ^ { 2 } \theta - 2 \cos ^ { 2 } \theta = 1$$ giving your answers to 1 decimal place.