CAIE P1 2010 November — Question 7 7 marks

Exam BoardCAIE
ModuleP1 (Pure Mathematics 1)
Year2010
SessionNovember
Marks7
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicComposite & Inverse Functions
TypePiecewise function inverses
DifficultyStandard +0.3 This is a straightforward piecewise function question requiring students to find the range, sketch the inverse by reflection, and find inverse expressions for two simple functions (quadratic and linear). While it involves multiple parts, each step uses standard techniques taught in P1 with no novel problem-solving required, making it slightly easier than average.
Spec1.02u Functions: definition and vocabulary (domain, range, mapping)1.02v Inverse and composite functions: graphs and conditions for existence

7 \includegraphics[max width=\textwidth, alt={}, center]{32a57386-2696-4fda-a3cb-ca0c5c3be432-3_778_816_255_662} The diagram shows the function f defined for \(0 \leqslant x \leqslant 6\) by $$\begin{aligned} & x \mapsto \frac { 1 } { 2 } x ^ { 2 } \quad \text { for } 0 \leqslant x \leqslant 2 , \\ & x \mapsto \frac { 1 } { 2 } x + 1 \text { for } 2 < x \leqslant 6 . \end{aligned}$$
  1. State the range of f .
  2. Copy the diagram and on your copy sketch the graph of \(y = \mathrm { f } ^ { - 1 } ( x )\).
  3. Obtain expressions to define \(\mathrm { f } ^ { - 1 } ( x )\), giving the set of values of \(x\) for which each expression is valid.

Question 7:
Part (i):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
Range is \(0 \leq f(x) \leq 4\), 0 to 4B1 Accept in two parts; Condone \(<\)
[1]
Part (ii):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(y = x\) drawn or impliedB1
Correct sketch of \(f^{-1}\)B1 SC if f missing, \((2,2)\ (4,6)\) must be shown
[2]
Part (iii):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\((x \mapsto)\sqrt{2x}\) for \(0 \leq x \leq 2\)B1B1 Condone \(<\ <\)
\((x \mapsto)2x - 2\) for \(2 < x \leq 4\)B1B1
[4]
## Question 7:

### Part (i):
| Answer/Working | Marks | Guidance |
|---|---|---|
| Range is $0 \leq f(x) \leq 4$, 0 to 4 | B1 | Accept in two parts; Condone $<$ |
| **[1]** | | |

### Part (ii):
| Answer/Working | Marks | Guidance |
|---|---|---|
| $y = x$ drawn or implied | B1 | |
| Correct sketch of $f^{-1}$ | B1 | SC if f missing, $(2,2)\ (4,6)$ must be shown |
| **[2]** | | |

### Part (iii):
| Answer/Working | Marks | Guidance |
|---|---|---|
| $(x \mapsto)\sqrt{2x}$ for $0 \leq x \leq 2$ | B1B1 | Condone $<\ <$ |
| $(x \mapsto)2x - 2$ for $2 < x \leq 4$ | B1B1 | |
| **[4]** | | |

---
7\\
\includegraphics[max width=\textwidth, alt={}, center]{32a57386-2696-4fda-a3cb-ca0c5c3be432-3_778_816_255_662}

The diagram shows the function f defined for $0 \leqslant x \leqslant 6$ by

$$\begin{aligned}
& x \mapsto \frac { 1 } { 2 } x ^ { 2 } \quad \text { for } 0 \leqslant x \leqslant 2 , \\
& x \mapsto \frac { 1 } { 2 } x + 1 \text { for } 2 < x \leqslant 6 .
\end{aligned}$$

(i) State the range of f .\\
(ii) Copy the diagram and on your copy sketch the graph of $y = \mathrm { f } ^ { - 1 } ( x )$.\\
(iii) Obtain expressions to define $\mathrm { f } ^ { - 1 } ( x )$, giving the set of values of $x$ for which each expression is valid.

\hfill \mbox{\textit{CAIE P1 2010 Q7 [7]}}