- In this question you must show all stages of your working.
Solutions relying entirely on calculator technology are not acceptable.
- Show that
$$3 \cos \theta ( \tan \theta \sin \theta + 3 ) = 11 - 5 \cos \theta$$
may be written as
$$3 \cos ^ { 2 } \theta - 14 \cos \theta + 8 = 0$$
- Hence solve, for \(0 < x < 360 ^ { \circ }\)
$$3 \cos 2 x ( \tan 2 x \sin 2 x + 3 ) = 11 - 5 \cos 2 x$$
giving your answers to one decimal place.