Edexcel C1 — Question 9 11 marks

Exam BoardEdexcel
ModuleC1 (Core Mathematics 1)
Marks11
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicArithmetic Sequences and Series
TypeProve sum formula
DifficultyModerate -0.8 Part (a) is a standard bookwork proof of the arithmetic series formula that appears in every C1 textbook. Parts (b) and (c) involve straightforward application of the formula to a context problem with simple simultaneous equations. This is routine practice material with no novel problem-solving required.
Spec1.04h Arithmetic sequences: nth term and sum formulae

9. An arithmetic series has first term \(a\) and common difference \(d\).
  1. Prove that the sum of the first \(n\) terms of the series is \(\frac { 1 } { 2 } n [ 2 a + ( n - 1 ) d ] .\) (4)
    A polygon has 16 sides. The lengths of the sides of the polygon, starting with the shortest side, form an arithmetic sequence with common difference \(d \mathrm {~cm}\).
    The longest side of the polygon has length 6 cm and the perimeter of the polygon is 72 cm .
    Find
  2. the length of the shortest side of the polygon,
    (5)
  3. the value of \(d\).
    (2) \(\_\_\_\_\) \(\_\_\_\_\) \(\_\_\_\_\) \(\_\_\_\_\) \(\_\_\_\_\) \(\_\_\_\_\) \(\_\_\_\_\) \(\_\_\_\_\) \(\_\_\_\_\) \(\_\_\_\_\) \(\_\_\_\_\) \(\_\_\_\_\) \(\_\_\_\_\) \(\_\_\_\_\) \(\_\_\_\_\) \(\_\_\_\_\) \(\_\_\_\_\) \(\_\_\_\_\) \(\_\_\_\_\) \(\_\_\_\_\) \(\_\_\_\_\) \(\_\_\_\_\) \end{tabular} & Leave blank
    \hline \end{tabular} \end{center}
    Leave blank
    \begin{center} \begin{tabular}{|l|l|} \hline \begin{tabular}{l}

Question 9:
Part (a):
AnswerMarks Guidance
\(S = a + (a+d) + \ldots + [a+(n-1)d]\)B1
\(S = [a+(n-1)d] + \ldots + a\)M1
Add: \(2S = n[2a+(n-1)d]\), \(\therefore S = \frac{1}{2}n[2a+(n-1)d]\) \((*)\)M1 A1 4 marks
Part (b):
AnswerMarks Guidance
\(a + 15d = 6\)B1
\(\frac{1}{2}n[2a+(n-1)d] = 8(2a+15d) = 72\)M1 A1
Solve simultaneously: \(a = 3\)M1 A1 5 marks
Part (c):
AnswerMarks Guidance
\(a=3\): \(15d = 6-3 = 3\), \(d = 0.2\)M1 A1 2 marks
Total: 11 marks
## Question 9:

### Part (a):
$S = a + (a+d) + \ldots + [a+(n-1)d]$ | B1 |

$S = [a+(n-1)d] + \ldots + a$ | M1 |

Add: $2S = n[2a+(n-1)d]$, $\therefore S = \frac{1}{2}n[2a+(n-1)d]$ $(*)$ | M1 A1 | **4 marks**

### Part (b):
$a + 15d = 6$ | B1 |

$\frac{1}{2}n[2a+(n-1)d] = 8(2a+15d) = 72$ | M1 A1 |

Solve simultaneously: $a = 3$ | M1 A1 | **5 marks**

### Part (c):
$a=3$: $15d = 6-3 = 3$, $d = 0.2$ | M1 A1 | **2 marks**

**Total: 11 marks**

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9. An arithmetic series has first term $a$ and common difference $d$.
\begin{enumerate}[label=(\alph*)]
\item Prove that the sum of the first $n$ terms of the series is \(\frac { 1 } { 2 } n [ 2 a + ( n - 1 ) d ] .\) \\
(4) \\
A polygon has 16 sides. The lengths of the sides of the polygon, starting with the shortest side, form an arithmetic sequence with common difference $d \mathrm {~cm}$. \\
The longest side of the polygon has length 6 cm and the perimeter of the polygon is 72 cm . \\
Find
\item the length of the shortest side of the polygon, \\
(5)
\item the value of $d$. \\
(2) $\_\_\_\_$ $\_\_\_\_$ $\_\_\_\_$ $\_\_\_\_$ $\_\_\_\_$ $\_\_\_\_$ $\_\_\_\_$ $\_\_\_\_$ $\_\_\_\_$ $\_\_\_\_$ $\_\_\_\_$ $\_\_\_\_$ $\_\_\_\_$ $\_\_\_\_$ $\_\_\_\_$ $\_\_\_\_$ $\_\_\_\_$ $\_\_\_\_$ $\_\_\_\_$ $\_\_\_\_$ $\_\_\_\_$ $\_\_\_\_$ \\
\end{tabular} & Leave blank \\
\hline
\end{tabular}
\end{center}

\begin{center}
\begin{tabular}{|l|l|}
\hline
Leave blank &  \\
\hline
\end{tabular}
\end{center}

\begin{center}
\begin{tabular}{|l|l|}
\hline
\begin{tabular}{l}
\end{enumerate}

\hfill \mbox{\textit{Edexcel C1  Q9 [11]}}