Edexcel C1 2009 January — Question 7

Exam BoardEdexcel
ModuleC1 (Core Mathematics 1)
Year2009
SessionJanuary
TopicInequalities
7. The equation \(k x ^ { 2 } + 4 x + ( 5 - k ) = 0\), where \(k\) is a constant, has 2 different real solutions for \(x\).
  1. Show that \(k\) satisfies $$k ^ { 2 } - 5 k + 4 > 0 .$$
  2. Hence find the set of possible values of \(k\).
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