Edexcel C12 2018 June — Question 12 10 marks

Exam BoardEdexcel
ModuleC12 (Core Mathematics 1 & 2)
Year2018
SessionJune
Marks10
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicTrigonometric equations in context
TypeSolve shifted trig equation
DifficultyStandard +0.3 Part (i) is a straightforward phase-shifted sine equation requiring basic rearrangement and calculator work. Part (ii) involves using the Pythagorean identity to convert to a quadratic in cos θ, then solving—a standard C2 technique. Both parts are routine applications of well-practiced methods with no novel insight required, making this slightly easier than the average A-level question.
Spec1.05j Trigonometric identities: tan=sin/cos and sin^2+cos^2=11.05o Trigonometric equations: solve in given intervals

12. [In this question solutions based entirely on graphical or numerical methods are not acceptable.]
  1. Solve for \(0 \leqslant x < 360 ^ { \circ }\), $$5 \sin \left( x + 65 ^ { \circ } \right) + 2 = 0$$ giving your answers in degrees to one decimal place.
  2. Find, for \(0 \leqslant \theta < 2 \pi\), all the solutions of $$12 \sin ^ { 2 } \theta + \cos \theta = 6$$ giving your answers in radians to 3 significant figures.

Question 12:
Part (i):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(\sin(\ldots) = -\frac{2}{5}\)M1 Allow \(\text{invsin}\!\left(\frac{2}{5}\right)=23.6°\) or one of the given angles
\(\ldots = -23.6°\) (or \(203.6°\) or \(336.4°\))A1 In radians allow awrt 0.41, 2.73
\(x = 138.6°\) or \(271.4°\) (allow awrt)dM1 A1 dM1: subtracting 65 from any of their answers. A1: cao, withhold if extra solutions in \([0°, 360°]\)
[4 marks]
Part (ii):
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(12(1-\cos^2\theta) + \cos\theta = 6\)M1 Attempts to use \(\sin^2\theta = 1-\cos^2\theta\)
Solves three-term quadratic \(12\cos^2\theta - \cos\theta - 6 = 0\)dM1 Solves 3TQ; implied by sight of \(\pm\) correct values
\(\cos\theta = -\frac{2}{3}\) or \(\frac{3}{4}\)A1
\(\theta = 2.30, 3.98, 0.723\) or \(5.56\)M1 A1 A1 M1: inverse cosine for valid \(\cos\theta\). A1: two angles correct in degrees or radians. A1: all four correct (awrt), no extras. Condone 2.3 for 2.30
[6 marks]
# Question 12:

## Part (i):

| Answer/Working | Marks | Guidance |
|---|---|---|
| $\sin(\ldots) = -\frac{2}{5}$ | M1 | Allow $\text{invsin}\!\left(\frac{2}{5}\right)=23.6°$ or one of the given angles |
| $\ldots = -23.6°$ (or $203.6°$ or $336.4°$) | A1 | In radians allow awrt 0.41, 2.73 |
| $x = 138.6°$ or $271.4°$ (allow awrt) | dM1 A1 | dM1: subtracting 65 from any of their answers. A1: cao, withhold if extra solutions in $[0°, 360°]$ |

**[4 marks]**

## Part (ii):

| Answer/Working | Marks | Guidance |
|---|---|---|
| $12(1-\cos^2\theta) + \cos\theta = 6$ | M1 | Attempts to use $\sin^2\theta = 1-\cos^2\theta$ |
| Solves three-term quadratic $12\cos^2\theta - \cos\theta - 6 = 0$ | dM1 | Solves 3TQ; implied by sight of $\pm$ correct values |
| $\cos\theta = -\frac{2}{3}$ or $\frac{3}{4}$ | A1 | |
| $\theta = 2.30, 3.98, 0.723$ or $5.56$ | M1 A1 A1 | M1: inverse cosine for valid $\cos\theta$. A1: two angles correct in degrees or radians. A1: all four correct (awrt), no extras. Condone 2.3 for 2.30 |

**[6 marks]**

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12. [In this question solutions based entirely on graphical or numerical methods are not acceptable.]\\
(i) Solve for $0 \leqslant x < 360 ^ { \circ }$,

$$5 \sin \left( x + 65 ^ { \circ } \right) + 2 = 0$$

giving your answers in degrees to one decimal place.\\
(ii) Find, for $0 \leqslant \theta < 2 \pi$, all the solutions of

$$12 \sin ^ { 2 } \theta + \cos \theta = 6$$

giving your answers in radians to 3 significant figures.\\

\hfill \mbox{\textit{Edexcel C12 2018 Q12 [10]}}