Edexcel C12 2016 January — Question 8 6 marks

Exam BoardEdexcel
ModuleC12 (Core Mathematics 1 & 2)
Year2016
SessionJanuary
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicTrigonometric equations in context
TypeConvert sin/cos ratio to tan
DifficultyModerate -0.3 Part (a) is a straightforward manipulation (divide by cos x) to find tan x = 3/7. Part (b) requires recognizing the structural similarity and substituting u = 2θ + 30°, then solving tan u = 3/7 and back-substituting. This is a standard 'hence' question testing pattern recognition and angle manipulation, slightly easier than average due to its routine nature and clear signposting.
Spec1.05j Trigonometric identities: tan=sin/cos and sin^2+cos^2=11.05o Trigonometric equations: solve in given intervals

8. (a) Given that \(7 \sin x = 3 \cos x\), find the exact value of \(\tan x\).
(b) Hence solve for \(0 \leqslant \theta < 360 ^ { \circ }\) $$7 \sin \left( 2 \theta + 30 ^ { \circ } \right) = 3 \cos \left( 2 \theta + 30 ^ { \circ } \right)$$ giving your answers to one decimal place.
(Solutions based entirely on graphical or numerical methods are not acceptable.)

Question 8:
Part (a):
AnswerMarks Guidance
Answer/WorkingMark Guidance
\(\tan x = \frac{3}{7}\)B1 Exact equivalent accepted; recurring decimal \(0.428571...\) accepted but not rounded answer
Part (b):
AnswerMarks Guidance
Answer/WorkingMark Guidance
\(\tan(2\theta + 30) = \frac{3}{7}\)B1ft Correct equation or follow through from part (a); \(2\theta+30\) may be implied later by subtracting 30 then dividing by 2
\(\tan^{-1}\frac{3}{7}\) \((\alpha)\)M1 Finds arctan of \(\frac{3}{7}\); implied by value e.g. 23.19 or just \(\tan^{-1}\frac{3}{7}\)
One of \(\theta =\) awrt 87 or awrt 177 or awrt 267 or awrt 357A1
Follow through any of their final \(\theta\)s for \(\theta \pm 90n\) within rangeA1ft
All of \(\theta = 86.6, \ 176.6, \ 266.6, \ 356.6\)A1 All 4 correct to required accuracy; ignore extra answers outside range; lose last A mark for extra answers inside range
## Question 8:

### Part (a):
| Answer/Working | Mark | Guidance |
|---|---|---|
| $\tan x = \frac{3}{7}$ | B1 | Exact equivalent accepted; recurring decimal $0.428571...$ accepted but not rounded answer |

### Part (b):
| Answer/Working | Mark | Guidance |
|---|---|---|
| $\tan(2\theta + 30) = \frac{3}{7}$ | B1ft | Correct equation or follow through from part (a); $2\theta+30$ may be implied later by subtracting 30 then dividing by 2 |
| $\tan^{-1}\frac{3}{7}$ $(\alpha)$ | M1 | Finds arctan of $\frac{3}{7}$; implied by value e.g. 23.19 or just $\tan^{-1}\frac{3}{7}$ |
| One of $\theta =$ awrt 87 or awrt 177 or awrt 267 or awrt 357 | A1 | |
| Follow through any of their final $\theta$s for $\theta \pm 90n$ within range | A1ft | |
| All of $\theta = 86.6, \ 176.6, \ 266.6, \ 356.6$ | A1 | All 4 correct to required accuracy; ignore extra answers outside range; lose last A mark for extra answers inside range |

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8. (a) Given that $7 \sin x = 3 \cos x$, find the exact value of $\tan x$.\\
(b) Hence solve for $0 \leqslant \theta < 360 ^ { \circ }$

$$7 \sin \left( 2 \theta + 30 ^ { \circ } \right) = 3 \cos \left( 2 \theta + 30 ^ { \circ } \right)$$

giving your answers to one decimal place.\\
(Solutions based entirely on graphical or numerical methods are not acceptable.)\\

\hfill \mbox{\textit{Edexcel C12 2016 Q8 [6]}}