CAIE P1 2006 November — Question 9

Exam BoardCAIE
ModuleP1 (Pure Mathematics 1)
Year2006
SessionNovember
TopicChain Rule

9
\includegraphics[max width=\textwidth, alt={}, center]{dd2cb0ec-5df9-4d99-9e15-5ae1f1c07b96-4_387_903_799_623} The diagram shows an open container constructed out of \(200 \mathrm {~cm} ^ { 2 }\) of cardboard. The two vertical end pieces are isosceles triangles with sides \(5 x \mathrm {~cm} , 5 x \mathrm {~cm}\) and \(8 x \mathrm {~cm}\), and the two side pieces are rectangles of length \(y \mathrm {~cm}\) and width \(5 x \mathrm {~cm}\), as shown. The open top is a horizontal rectangle.
  1. Show that \(y = \frac { 200 - 24 x ^ { 2 } } { 10 x }\).
  2. Show that the volume, \(V \mathrm {~cm} ^ { 3 }\), of the container is given by \(V = 240 x - 28.8 x ^ { 3 }\). Given that \(x\) can vary,
  3. find the value of \(x\) for which \(V\) has a stationary value,
  4. determine whether it is a maximum or a minimum stationary value.