Edexcel P1 2023 June — Question 3 6 marks

Exam BoardEdexcel
ModuleP1 (Pure Mathematics 1)
Year2023
SessionJune
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicCompleting the square and sketching
TypeComplete the square
DifficultyModerate -0.8 This is a straightforward completing-the-square exercise followed by a routine sketch. Part (a) requires standard algebraic manipulation with integer coefficients that factor nicely. Part (b) is direct application: the turning point comes immediately from the completed square form, and the y-intercept requires only substituting x=0. No problem-solving or insight needed—pure procedural recall.
Spec1.02e Complete the square: quadratic polynomials and turning points1.02n Sketch curves: simple equations including polynomials

  1. (a) Express \(3 x ^ { 2 } + 12 x + 13\) in the form
$$a ( x + b ) ^ { 2 } + c$$ where \(a\), \(b\) and \(c\) are integers to be found.
(b) Hence sketch the curve with equation \(y = 3 x ^ { 2 } + 12 x + 13\) On your sketch show clearly
  • the coordinates of the \(y\) intercept
  • the coordinates of the turning point of the curve

Question 3:
Part (a):
AnswerMarks Guidance
Answer/WorkingMark Guidance
\(a = 3\)B1 Correct value for \(a\) stated or shown by working
\(b = \pm 2\)M1 Obtains \(b = \pm 2\). Allow unsimplified e.g. \(b = \pm\frac{4}{2}, \pm\frac{12}{6}\)
\(3x^2 + 12x + 13 = 3(x+2)^2 + 1\) or \(a=3, b=2, c=1\)A1 Fully correct expression or correct values
Part (b):
AnswerMarks Guidance
Answer/WorkingMark Guidance
Correct U shape with minimum in second quadrantB1 Must be U shape, minimum not on \(x\)-axis, not a clear V shape
Intercept 13 on \(y\)-axisB1 Allow as just 13 or \((0,13)\) or \((13,0)\) if in correct position
Vertex at \((-2, 1)\)B1ft Follow through on their \(b\) and \(c\), i.e. \(x=-b\), \(y=c\). Must correspond to sketch.
# Question 3:

## Part (a):

| Answer/Working | Mark | Guidance |
|---|---|---|
| $a = 3$ | **B1** | Correct value for $a$ stated or shown by working |
| $b = \pm 2$ | **M1** | Obtains $b = \pm 2$. Allow unsimplified e.g. $b = \pm\frac{4}{2}, \pm\frac{12}{6}$ |
| $3x^2 + 12x + 13 = 3(x+2)^2 + 1$ or $a=3, b=2, c=1$ | **A1** | Fully correct expression or correct values |

## Part (b):

| Answer/Working | Mark | Guidance |
|---|---|---|
| Correct U shape with minimum in second quadrant | **B1** | Must be U shape, minimum not on $x$-axis, not a clear V shape |
| Intercept 13 on $y$-axis | **B1** | Allow as just 13 or $(0,13)$ or $(13,0)$ if in correct position |
| Vertex at $(-2, 1)$ | **B1ft** | Follow through on their $b$ and $c$, i.e. $x=-b$, $y=c$. Must correspond to sketch. |

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\begin{enumerate}
  \item (a) Express $3 x ^ { 2 } + 12 x + 13$ in the form
\end{enumerate}

$$a ( x + b ) ^ { 2 } + c$$

where $a$, $b$ and $c$ are integers to be found.\\
(b) Hence sketch the curve with equation $y = 3 x ^ { 2 } + 12 x + 13$

On your sketch show clearly

\begin{itemize}
  \item the coordinates of the $y$ intercept
  \item the coordinates of the turning point of the curve
\end{itemize}

\hfill \mbox{\textit{Edexcel P1 2023 Q3 [6]}}