Edexcel P1 2019 January — Question 1 4 marks

Exam BoardEdexcel
ModuleP1 (Pure Mathematics 1)
Year2019
SessionJanuary
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicStandard Integrals and Reverse Chain Rule
TypeFind indefinite integral of polynomial/power
DifficultyEasy -1.2 This is a straightforward application of standard integration rules for powers of x, requiring only recall of the formula ∫x^n dx = x^(n+1)/(n+1) + C and basic algebraic simplification. It's a routine P1/AS-level question with no problem-solving element, making it easier than average.
Spec1.08b Integrate x^n: where n != -1 and sums

  1. Find
$$\int \left( \frac { 2 } { 3 } x ^ { 3 } - \frac { 1 } { 2 x ^ { 3 } } + 5 \right) d x$$ simplifying your answer.

Question 1:
\[\int \frac{2}{3}x^3 - \frac{1}{2x^3} + 5 \, dx\]
AnswerMarks Guidance
Working/AnswerMarks Guidance
Raises any power by 1, e.g. \(x^3 \to x^4\), \(x^{-3} \to x^{-2}\), \(5 \to 5x\)M1 Must show attempt at integration
\(\frac{2}{3} \times \frac{x^4}{4} - \frac{1}{2} \times \frac{x^{-2}}{-2} + 5x + c\) (un-simplified, two correct terms)A1 Accept \(5x^1\)
\(\frac{1}{6}x^4 + \frac{1}{4}x^{-2} + 5x\) (two terms correct in simplest form)A1 Accept \(\frac{x^4}{6}\), \(\frac{1}{4x^2}\); CONDONE \(+\frac{0.25}{x^2}\); NOT \(\frac{1/4}{x^2}\), \(\frac{5x}{1}\), \(-\left(-\frac{1}{4}x^{-2}\right)\)
\(= \frac{1}{6}x^4 + \frac{1}{4}x^{-2} + 5x + c\) fully correct and simplifiedA1 Must have \(+c\); ISW after correct simplified answer
## Question 1:

$$\int \frac{2}{3}x^3 - \frac{1}{2x^3} + 5 \, dx$$

| Working/Answer | Marks | Guidance |
|---|---|---|
| Raises any power by 1, e.g. $x^3 \to x^4$, $x^{-3} \to x^{-2}$, $5 \to 5x$ | M1 | Must show attempt at integration |
| $\frac{2}{3} \times \frac{x^4}{4} - \frac{1}{2} \times \frac{x^{-2}}{-2} + 5x + c$ (un-simplified, two correct terms) | A1 | Accept $5x^1$ |
| $\frac{1}{6}x^4 + \frac{1}{4}x^{-2} + 5x$ (two terms correct in simplest form) | A1 | Accept $\frac{x^4}{6}$, $\frac{1}{4x^2}$; CONDONE $+\frac{0.25}{x^2}$; NOT $\frac{1/4}{x^2}$, $\frac{5x}{1}$, $-\left(-\frac{1}{4}x^{-2}\right)$ |
| $= \frac{1}{6}x^4 + \frac{1}{4}x^{-2} + 5x + c$ fully correct and simplified | A1 | Must have $+c$; ISW after correct simplified answer |

---
\begin{enumerate}
  \item Find
\end{enumerate}

$$\int \left( \frac { 2 } { 3 } x ^ { 3 } - \frac { 1 } { 2 x ^ { 3 } } + 5 \right) d x$$

simplifying your answer.\\

\hfill \mbox{\textit{Edexcel P1 2019 Q1 [4]}}