CAIE P1 2003 November — Question 9 11 marks

Exam BoardCAIE
ModuleP1 (Pure Mathematics 1)
Year2003
SessionNovember
Marks11
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicVolumes of Revolution
TypeMulti-part: volume and tangent/normal
DifficultyStandard +0.3 This is a straightforward volumes of revolution question combined with basic tangent finding. Part (i) requires standard differentiation and straight line geometry. Part (ii) is a routine integration of a rational function for volume of revolution. All techniques are standard P1/C2 level with no novel insights required, making it slightly easier than average.
Spec1.07l Derivative of ln(x): and related functions1.07m Tangents and normals: gradient and equations4.08d Volumes of revolution: about x and y axes

9 \includegraphics[max width=\textwidth, alt={}, center]{1cf37a58-8a7f-4dc8-9e35-2e8badf3eb83-4_563_679_938_733} The diagram shows points \(A ( 0,4 )\) and \(B ( 2,1 )\) on the curve \(y = \frac { 8 } { 3 x + 2 }\). The tangent to the curve at \(B\) crosses the \(x\)-axis at \(C\). The point \(D\) has coordinates \(( 2,0 )\).
  1. Find the equation of the tangent to the curve at \(B\) and hence show that the area of triangle \(B D C\) is \(\frac { 4 } { 3 }\).
  2. Show that the volume of the solid formed when the shaded region \(O D B A\) is rotated completely about the \(x\)-axis is \(8 \pi\).

(i) \(\frac{dy}{dx} = \frac{-24}{(3x+2)^2}\)
Eqn of tangent: \(y-1=\frac{3}{8}(x-2)\)
AnswerMarks Guidance
Cuts \(y=0\) when \(x=4\frac{2}{3}\)M1, A1, A1 [6] Use of fn of fn. Needs \(\times 3\) for M mark. Co. Use of line form with \(\frac{dy}{dx}\). Must use calculus. \(\surd\) on his \(\frac{dy}{dx}\). Normal M0. Needs \(y=0\) and \(\frac{1}{2}bh\) for M mark. (beware fortuitous answers).
Area of Q \(= \frac{1}{2} \times 2\frac{2}{3} \times 1 = \frac{4}{3}\)M1, A1, ∇ [6]
(ii) Vol \(=\pi \int y^2dx = \pi[64(3x+2)^{-2} \times 3]\) limits from 0 to 2
AnswerMarks Guidance
\(\rightarrow 8\pi\)M1, A1, A1, DM1, A1 [5] Uses \(\int y^2 +\) some integration \(\rightarrow (3x+2)^k\). A1 without the \(-3\). A1 for \(-3\) and \(\pi\). DMO if 0 ignored. Co. Beware fortuitous answers.
**(i)** $\frac{dy}{dx} = \frac{-24}{(3x+2)^2}$
Eqn of tangent: $y-1=\frac{3}{8}(x-2)$
Cuts $y=0$ when $x=4\frac{2}{3}$ | M1, A1, A1 [6] | Use of fn of fn. Needs $\times 3$ for M mark. Co. Use of line form with $\frac{dy}{dx}$. Must use calculus. $\surd$ on his $\frac{dy}{dx}$. Normal M0. Needs $y=0$ and $\frac{1}{2}bh$ for M mark. (beware fortuitous answers).
Area of Q $= \frac{1}{2} \times 2\frac{2}{3} \times 1 = \frac{4}{3}$ | M1, A1, ∇ [6] |

**(ii)** Vol $=\pi \int y^2dx = \pi[64(3x+2)^{-2} \times 3]$ limits from 0 to 2
$\rightarrow 8\pi$ | M1, A1, A1, DM1, A1 [5] | Uses $\int y^2 +$ some integration $\rightarrow (3x+2)^k$. A1 without the $-3$. A1 for $-3$ and $\pi$. DMO if 0 ignored. Co. Beware fortuitous answers.
9\\
\includegraphics[max width=\textwidth, alt={}, center]{1cf37a58-8a7f-4dc8-9e35-2e8badf3eb83-4_563_679_938_733}

The diagram shows points $A ( 0,4 )$ and $B ( 2,1 )$ on the curve $y = \frac { 8 } { 3 x + 2 }$. The tangent to the curve at $B$ crosses the $x$-axis at $C$. The point $D$ has coordinates $( 2,0 )$.\\
(i) Find the equation of the tangent to the curve at $B$ and hence show that the area of triangle $B D C$ is $\frac { 4 } { 3 }$.\\
(ii) Show that the volume of the solid formed when the shaded region $O D B A$ is rotated completely about the $x$-axis is $8 \pi$.

\hfill \mbox{\textit{CAIE P1 2003 Q9 [11]}}