CAIE S2 2014 November — Question 4 10 marks

Exam BoardCAIE
ModuleS2 (Statistics 2)
Year2014
SessionNovember
Marks10
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TopicLinear combinations of normal random variables
TypeMixed sum threshold probability
DifficultyStandard +0.8 This question requires understanding of linear combinations of normal distributions and forming appropriate combinations (4A + 6B for part i, A - 0.9B for part ii). While the mechanics are standard S2 content, students must correctly identify the required distributions, handle the unit conversion in part (i), and recognize the less obvious 90% comparison structure in part (ii), making it moderately challenging.
Spec5.04a Linear combinations: E(aX+bY), Var(aX+bY)5.04b Linear combinations: of normal distributions

4 The masses, in grams, of tomatoes of type \(A\) and type \(B\) have the distributions \(\mathrm { N } \left( 125,30 ^ { 2 } \right)\) and \(\mathrm { N } \left( 130,32 ^ { 2 } \right)\) respectively.
  1. Find the probability that the total mass of 4 randomly chosen tomatoes of type \(A\) and 6 randomly chosen tomatoes of type \(B\) is less than 1.5 kg .
  2. Find the probability that a randomly chosen tomato of type \(A\) has a mass that is at least \(90 \%\) of the mass of a randomly chosen tomato of type \(B\).

AnswerMarks Guidance
Part (i)
\(4 \times 125 + 6 \times 130 (= 1280)\)B1 Give at early stage. Could be implied by 220. (If B0B0 then 1.28 and 0.009744 can score B1B1).
\(4 \times 30^2 + 6 \times 32^2 (= 9744)\)B1
\((\pm)\frac{1500-1280}{\sqrt{9744}}(= 2.229)\)M1 Standardising. Accept sd/var mix. Must be from combination attempt.
\(\Phi('2.229')\)M1 Use of tables and correct area consistent with their working
\(= 0.987\) (3 sf)A1 [5] cwo
Part (ii)
\(125 - 0.9(130) (= 8)\) (or \(-8\))B1 Give at early stage. (If B0B0 scored then accept 0.008 and 0.0017944 for B1B1)
\(30^2 + 0.9^2(32^2) (= 1729.44)\)B1
\((\pm)\frac{0-'8'}{\sqrt{1729.44}}(= -0.192)\)M1 Accept sd/var mix. Must come from a linear combination.
\(\Phi('0.192')\)M1 Use of tables and correct area consistent with their working (unclear M0)
\(= 0.576\) (3 sf)A1 [5]
Total[10]
| **Part (i)** |
|---|
| $4 \times 125 + 6 \times 130 (= 1280)$ | B1 | Give at early stage. Could be implied by 220. (If B0B0 then 1.28 and 0.009744 can score B1B1). |
| $4 \times 30^2 + 6 \times 32^2 (= 9744)$ | B1 | |
| $(\pm)\frac{1500-1280}{\sqrt{9744}}(= 2.229)$ | M1 | Standardising. Accept sd/var mix. Must be from combination attempt. |
| $\Phi('2.229')$ | M1 | Use of tables and correct area consistent with their working |
| $= 0.987$ (3 sf) | A1 | [5] cwo |

| **Part (ii)** |
|---|
| $125 - 0.9(130) (= 8)$ (or $-8$) | B1 | Give at early stage. (If B0B0 scored then accept 0.008 and 0.0017944 for B1B1) |
| $30^2 + 0.9^2(32^2) (= 1729.44)$ | B1 | |
| $(\pm)\frac{0-'8'}{\sqrt{1729.44}}(= -0.192)$ | M1 | Accept sd/var mix. Must come from a linear combination. |
| $\Phi('0.192')$ | M1 | Use of tables and correct area consistent with their working (unclear M0) |
| $= 0.576$ (3 sf) | A1 | [5] |

| **Total** | [10] |
4 The masses, in grams, of tomatoes of type $A$ and type $B$ have the distributions $\mathrm { N } \left( 125,30 ^ { 2 } \right)$ and $\mathrm { N } \left( 130,32 ^ { 2 } \right)$ respectively.\\
(i) Find the probability that the total mass of 4 randomly chosen tomatoes of type $A$ and 6 randomly chosen tomatoes of type $B$ is less than 1.5 kg .\\
(ii) Find the probability that a randomly chosen tomato of type $A$ has a mass that is at least $90 \%$ of the mass of a randomly chosen tomato of type $B$.

\hfill \mbox{\textit{CAIE S2 2014 Q4 [10]}}