CAIE S2 2012 June — Question 7 10 marks

Exam BoardCAIE
ModuleS2 (Statistics 2)
Year2012
SessionJune
Marks10
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicContinuous Probability Distributions and Random Variables
TypeSingle-piece PDF with k
DifficultyStandard +0.3 This is a straightforward continuous probability distribution question requiring standard techniques: integrating to find k, solving for the median using cumulative distribution, and computing E(X). The integration of sin x is routine, and all three parts follow predictable methods with no novel problem-solving required. Slightly above average difficulty only due to the multi-part nature and need for numerical solving in part (ii).
Spec5.03a Continuous random variables: pdf and cdf5.03b Solve problems: using pdf5.03c Calculate mean/variance: by integration5.03f Relate pdf-cdf: medians and percentiles

7 \includegraphics[max width=\textwidth, alt={}, center]{7333c047-edad-4385-b3f8-248e8725cfcb-3_412_718_1037_715} A random variable \(X\) has probability density function given by $$f ( x ) = \begin{cases} k \sin x & 0 \leqslant x \leqslant \frac { 2 } { 3 } \pi \\ 0 & \text { otherwise } \end{cases}$$ where \(k\) is a constant, as shown in the diagram.
  1. Show that \(k = \frac { 2 } { 3 }\).
  2. Show that the median of \(X\) is 1.32 , correct to 3 significant figures.
  3. Find \(\mathrm { E } ( X )\).

Question 7:
Part (i)
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(k\int_0^{\frac{2\pi}{3}} \sin x \, dx = 1\)M1 Integ \(k = 1\), ignore limits
\(k[-\cos x]_0^{\frac{2\pi}{3}}\)
\(k\left[-\cos\frac{2\pi}{3} + \cos 0\right] = 1\) Must see this line or next
\(k[0.5 + 1] = 1\)
\(k = \frac{2}{3}\) (AG)A1 (2)
Part (ii)
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(\frac{2}{3}\int_0^m \sin x \, dx = 0.5\)M1* Integ \(k = 0.5\), ignore limits
\(\frac{2}{3}[-\cos x]_0^m = 0.5\)M1* dep Correct integrand & limits 0 to unknown, \(= 0.5\)
\(\frac{2}{3}(-\cos m + 1) = 0.5\)
\(\cos m = 0.25\)A1 But allow \(a\cos m = b\) where \(b/a = 0.25\); dep \(\cos m = 0.25\) seen
\(m = 1.32\) (3 sf) (AG)A1 (4) NB accept full verification
Part (iii)
AnswerMarks Guidance
Answer/WorkingMarks Guidance
\(\frac{2}{3}\int_0^{\frac{2\pi}{3}} x\sin x \, dx\)M1 Integ \(xf(x)\), ignore limits
\(= \frac{2}{3}\left\{[x(-\cos x)]_0^{\frac{2\pi}{3}} - \int_0^{\frac{2\pi}{3}}(-\cos x)\,dx\right\}\)M1* dep 1st step attempted i.e. \(x(-\cos x)\), ignore limits
\(= \frac{2}{3}\left\{\frac{\pi}{3} - 0 - [-\sin x]_0^{\frac{2\pi}{3}}\right\}\)M1* dep 2nd step attempted including correct limits applied
\(= \frac{2}{3}\left(\frac{\pi}{3} + \sin\frac{2\pi}{3}\right)\)
\(= \frac{2\pi + 3\sqrt{3}}{9}\) or \(1.28\) (3 sf)A1 (4) oe
## Question 7:

### Part (i)
| Answer/Working | Marks | Guidance |
|---|---|---|
| $k\int_0^{\frac{2\pi}{3}} \sin x \, dx = 1$ | M1 | Integ $k = 1$, ignore limits |
| $k[-\cos x]_0^{\frac{2\pi}{3}}$ | | |
| $k\left[-\cos\frac{2\pi}{3} + \cos 0\right] = 1$ | | Must see this line or next |
| $k[0.5 + 1] = 1$ | | |
| $k = \frac{2}{3}$ (AG) | A1 (2) | |

### Part (ii)
| Answer/Working | Marks | Guidance |
|---|---|---|
| $\frac{2}{3}\int_0^m \sin x \, dx = 0.5$ | M1* | Integ $k = 0.5$, ignore limits |
| $\frac{2}{3}[-\cos x]_0^m = 0.5$ | M1* dep | Correct integrand & limits 0 to unknown, $= 0.5$ |
| $\frac{2}{3}(-\cos m + 1) = 0.5$ | | |
| $\cos m = 0.25$ | A1 | But allow $a\cos m = b$ where $b/a = 0.25$; dep $\cos m = 0.25$ seen |
| $m = 1.32$ (3 sf) (AG) | A1 (4) | NB accept full verification |

### Part (iii)
| Answer/Working | Marks | Guidance |
|---|---|---|
| $\frac{2}{3}\int_0^{\frac{2\pi}{3}} x\sin x \, dx$ | M1 | Integ $xf(x)$, ignore limits |
| $= \frac{2}{3}\left\{[x(-\cos x)]_0^{\frac{2\pi}{3}} - \int_0^{\frac{2\pi}{3}}(-\cos x)\,dx\right\}$ | M1* dep | 1st step attempted i.e. $x(-\cos x)$, ignore limits |
| $= \frac{2}{3}\left\{\frac{\pi}{3} - 0 - [-\sin x]_0^{\frac{2\pi}{3}}\right\}$ | M1* dep | 2nd step attempted including correct limits applied |
| $= \frac{2}{3}\left(\frac{\pi}{3} + \sin\frac{2\pi}{3}\right)$ | | |
| $= \frac{2\pi + 3\sqrt{3}}{9}$ or $1.28$ (3 sf) | A1 (4) | oe |
7\\
\includegraphics[max width=\textwidth, alt={}, center]{7333c047-edad-4385-b3f8-248e8725cfcb-3_412_718_1037_715}

A random variable $X$ has probability density function given by

$$f ( x ) = \begin{cases} k \sin x & 0 \leqslant x \leqslant \frac { 2 } { 3 } \pi \\ 0 & \text { otherwise } \end{cases}$$

where $k$ is a constant, as shown in the diagram.\\
(i) Show that $k = \frac { 2 } { 3 }$.\\
(ii) Show that the median of $X$ is 1.32 , correct to 3 significant figures.\\
(iii) Find $\mathrm { E } ( X )$.

\hfill \mbox{\textit{CAIE S2 2012 Q7 [10]}}