CAIE S2 2010 June — Question 5 8 marks

Exam BoardCAIE
ModuleS2 (Statistics 2)
Year2010
SessionJune
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicContinuous Probability Distributions and Random Variables
TypeSingle-piece PDF with k
DifficultyModerate -0.3 This is a straightforward continuous probability distribution question requiring standard techniques: integrating the pdf to find k, then computing E(X) and Var(X) using standard formulas. The integration is routine (power rule), and all steps are textbook exercises with no problem-solving insight needed. Slightly easier than average due to the simple algebraic form.
Spec5.03a Continuous random variables: pdf and cdf5.03c Calculate mean/variance: by integration

5 The time, in minutes, taken by volunteers to complete a task is modelled by the random variable \(X\) with probability density function given by $$\mathrm { f } ( x ) = \begin{cases} \frac { k } { x ^ { 4 } } & x \geqslant 1 \\ 0 & \text { otherwise. } \end{cases}$$
  1. Show that \(k = 3\).
  2. Find \(\mathrm { E } ( X )\) and \(\operatorname { Var } ( X )\).

AnswerMarks Guidance
(i) \(\int_1^{\infty} \frac{k}{x^2} dx = 1\)M1 Attempt integ f(x) & "= 1"; ignore limits
\(\left[-\frac{k}{3x^3}\right]_1^{\infty} = 1 \infty\) Correct integrand & limits leading to AG, no errors seen
\((0 + \frac{k}{3} = 1 \Rightarrow k = 3\) AG)A1 [2]
(ii) \(\int_1^{\infty} x \times \frac{3}{x^4} dx\)M1 Attempt integ xf(x); ignore limits.
\(\left[-\frac{3}{2x^2}\right]_1^{\infty}\)
\(= \frac{3}{2}\)A1 CWO
\(\int_1^{\infty} x^2 \times \frac{3}{x^4} dx\)M1* Attempt integ \(x^2f(x)\); ignore limits.
\(\left[-\frac{3}{x}\right]_1^{\infty} (= 3)\)A1 Correct integrand; correct limits
"3" \(= \left(3 \times \frac{\alpha}{2}\right)\)M1*dep dep 2nd M1 attempt E(\(X^2\)) – [E(\(X\))]²
\(= \frac{3}{4}\)A1 cwo
[6]
**(i)** $\int_1^{\infty} \frac{k}{x^2} dx = 1$ | M1 | Attempt integ f(x) & "= 1"; ignore limits
$\left[-\frac{k}{3x^3}\right]_1^{\infty} = 1 \infty$ | | Correct integrand & limits leading to AG, no errors seen
$(0 + \frac{k}{3} = 1 \Rightarrow k = 3$ **AG)** | A1 [2] |

**(ii)** $\int_1^{\infty} x \times \frac{3}{x^4} dx$ | M1 | Attempt integ xf(x); ignore limits.
$\left[-\frac{3}{2x^2}\right]_1^{\infty}$ | | 
$= \frac{3}{2}$ | A1 | CWO

$\int_1^{\infty} x^2 \times \frac{3}{x^4} dx$ | M1* | Attempt integ $x^2f(x)$; ignore limits.
$\left[-\frac{3}{x}\right]_1^{\infty} (= 3)$ | A1 | Correct integrand; correct limits
"3" $= \left(3 \times \frac{\alpha}{2}\right)$ | M1*dep | dep 2nd M1 attempt E($X^2$) – [E($X$)]²
$= \frac{3}{4}$ | A1 | cwo
 | [6] |
5 The time, in minutes, taken by volunteers to complete a task is modelled by the random variable $X$ with probability density function given by

$$\mathrm { f } ( x ) = \begin{cases} \frac { k } { x ^ { 4 } } & x \geqslant 1 \\ 0 & \text { otherwise. } \end{cases}$$

(i) Show that $k = 3$.\\
(ii) Find $\mathrm { E } ( X )$ and $\operatorname { Var } ( X )$.

\hfill \mbox{\textit{CAIE S2 2010 Q5 [8]}}