CAIE S2 2016 June — Question 4 6 marks

Exam BoardCAIE
ModuleS2 (Statistics 2)
Year2016
SessionJune
Marks6
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicZ-tests (known variance)
TypeTwo-tail z-test
DifficultyModerate -0.3 This is a straightforward two-tail z-test application with given values that plug directly into the standard formula. Part (i) requires calculating a test statistic and comparing to critical values (routine procedure), while part (ii) tests basic understanding that significance level equals Type I error probability (definitional recall). No problem-solving insight or complex reasoning required.
Spec2.05a Hypothesis testing language: null, alternative, p-value, significance5.05c Hypothesis test: normal distribution for population mean

4 In the past, the time spent by customers in a certain shop had mean 12.5 minutes and standard deviation 4.2 minutes. Following a change of layout in the shop, the mean time spent in the shop by a random sample of 50 customers is found to be 13.5 minutes.
  1. Assuming that the standard deviation remains at 4.2 minutes, test at the \(5 \%\) significance level whether the mean time spent by customers in the shop has changed.
  2. Another random sample of 50 customers is chosen and a similar test at the \(5 \%\) significance level is carried out. State the probability of a Type I error.

Question 4:
Part (i):
AnswerMarks Guidance
Answer/WorkingMark Guidance
\(H_0: \mu = 12.5\); \(H_1: \mu \neq 12.5\)B1
\(\frac{13.5 - 12.5}{4.2 \div \sqrt{50}}\)M1 allow \(4.2 \div 50\)
\(= 1.68(4)\)A1
\(`1.684` < 1.96\)M1 comp 1.96 allow comp 1.645 if \(H_1: \mu > 12.5\); or comp \(1 -\) ('1.684') with 0.025
No evidence that mean time has changedA1ft [5] No contradictions; ft their 1.684, but not comp 1.645
Part (ii):
AnswerMarks Guidance
Answer/WorkingMark Guidance
0.05B1 [1]
## Question 4:

### Part (i):
| Answer/Working | Mark | Guidance |
|---|---|---|
| $H_0: \mu = 12.5$; $H_1: \mu \neq 12.5$ | B1 | |
| $\frac{13.5 - 12.5}{4.2 \div \sqrt{50}}$ | M1 | allow $4.2 \div 50$ |
| $= 1.68(4)$ | A1 | |
| $`1.684` < 1.96$ | M1 | comp 1.96 allow comp 1.645 if $H_1: \mu > 12.5$; or comp $1 -$ ('1.684') with 0.025 |
| No evidence that mean time has changed | A1ft [5] | No contradictions; ft their 1.684, but not comp 1.645 |

### Part (ii):
| Answer/Working | Mark | Guidance |
|---|---|---|
| 0.05 | B1 [1] | |

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4 In the past, the time spent by customers in a certain shop had mean 12.5 minutes and standard deviation 4.2 minutes. Following a change of layout in the shop, the mean time spent in the shop by a random sample of 50 customers is found to be 13.5 minutes.\\
(i) Assuming that the standard deviation remains at 4.2 minutes, test at the $5 \%$ significance level whether the mean time spent by customers in the shop has changed.\\
(ii) Another random sample of 50 customers is chosen and a similar test at the $5 \%$ significance level is carried out. State the probability of a Type I error.

\hfill \mbox{\textit{CAIE S2 2016 Q4 [6]}}