CAIE P1 2018 June — Question 8 8 marks

Exam BoardCAIE
ModuleP1 (Pure Mathematics 1)
Year2018
SessionJune
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicChain Rule
TypeTangent with specified gradient
DifficultyModerate -0.3 Part (i) requires finding where dy/dx equals -3 (gradient matching), then substituting to find the point and tangent equation—straightforward differentiation and algebra. Part (ii) involves finding where f'(x) ≥ 0 always, requiring completing the square or finding the vertex of a quadratic. Both parts are standard textbook exercises with no novel insight required, making this slightly easier than average.
Spec1.07m Tangents and normals: gradient and equations1.07o Increasing/decreasing: functions using sign of dy/dx

8
  1. The tangent to the curve \(y = x ^ { 3 } - 9 x ^ { 2 } + 24 x - 12\) at a point \(A\) is parallel to the line \(y = 2 - 3 x\). Find the equation of the tangent at \(A\).
  2. The function f is defined by \(\mathrm { f } ( x ) = x ^ { 3 } - 9 x ^ { 2 } + 24 x - 12\) for \(x > k\), where \(k\) is a constant. Find the smallest value of \(k\) for f to be an increasing function.

Question 8(i):
AnswerMarks Guidance
AnswerMarks Guidance
\(\frac{dy}{dx} = 3x^2 - 18x + 24\)M1A1 Attempt to differentiate. All correct for A mark
\(3x^2 - 18x + 24 = -3\)M1 Equate their \(\frac{dy}{dx}\) to \(-3\)
\(x = 3\)A1
\(y = 6\)A1
\(y - 6 = -3(x-3)\)A1FT FT on their A. Expect \(y = -3x + 15\)
6
Question 8(ii):
AnswerMarks Guidance
AnswerMarks Guidance
\((3)(x-2)(x-4)\) SOI or \(x=2,\ 4\). Allow \((3)(x+2)(x+4)\)M1 Attempt to factorise or solve. Ignore a RHS, e.g. \(= 0\) or \(> 0\), etc.
Smallest value of \(k\) is 4A1 Allow \(k \geqslant 4\). Allow \(k = 4\). Must be in terms of \(k\)
2
## Question 8(i):

| Answer | Marks | Guidance |
|--------|-------|----------|
| $\frac{dy}{dx} = 3x^2 - 18x + 24$ | M1A1 | Attempt to differentiate. All correct for A mark |
| $3x^2 - 18x + 24 = -3$ | M1 | Equate their $\frac{dy}{dx}$ to $-3$ |
| $x = 3$ | A1 | |
| $y = 6$ | A1 | |
| $y - 6 = -3(x-3)$ | A1FT | FT on their A. Expect $y = -3x + 15$ |
| | **6** | |

## Question 8(ii):

| Answer | Marks | Guidance |
|--------|-------|----------|
| $(3)(x-2)(x-4)$ SOI or $x=2,\ 4$. Allow $(3)(x+2)(x+4)$ | M1 | Attempt to factorise or solve. Ignore a RHS, e.g. $= 0$ or $> 0$, etc. |
| Smallest value of $k$ is 4 | A1 | Allow $k \geqslant 4$. Allow $k = 4$. Must be in terms of $k$ |
| | **2** | |
8 (i) The tangent to the curve $y = x ^ { 3 } - 9 x ^ { 2 } + 24 x - 12$ at a point $A$ is parallel to the line $y = 2 - 3 x$. Find the equation of the tangent at $A$.\\

(ii) The function f is defined by $\mathrm { f } ( x ) = x ^ { 3 } - 9 x ^ { 2 } + 24 x - 12$ for $x > k$, where $k$ is a constant. Find the smallest value of $k$ for f to be an increasing function.\\

\hfill \mbox{\textit{CAIE P1 2018 Q8 [8]}}