Standard +0.3 This is a straightforward application of the confidence interval formula for proportions. Students need to recognize that the sample proportion is at the midpoint (0.4), calculate the margin of error (0.045), then use the formula with n=500 to find the z-value and convert to confidence level. It's slightly easier than average because it's a direct reverse calculation with no conceptual complications.
3 A random sample of 500 households in a certain town was chosen. Using this sample, a confidence interval for the proportion, \(p\), of all households in that town that owned two or more cars was found to be \(0.355 < p < 0.445\).
Find the confidence level of this confidence interval. Give your answer correct to the nearest integer.
3 A random sample of 500 households in a certain town was chosen. Using this sample, a confidence interval for the proportion, $p$, of all households in that town that owned two or more cars was found to be $0.355 < p < 0.445$.
Find the confidence level of this confidence interval. Give your answer correct to the nearest integer.\\
\hfill \mbox{\textit{CAIE S2 2022 Q3 [5]}}