CAIE S2 2020 March — Question 7 8 marks

Exam BoardCAIE
ModuleS2 (Statistics 2)
Year2020
SessionMarch
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicHypothesis test of binomial distributions
TypeOne-tailed test critical region
DifficultyStandard +0.3 This is a straightforward hypothesis testing question requiring standard binomial critical region calculations at a given significance level, followed by routine Type I and Type II error probability computations. While it involves multiple parts, each step follows textbook procedures without requiring novel insight or complex reasoning.
Spec5.05b Unbiased estimates: of population mean and variance

7 A national survey shows that \(95 \%\) of year 12 students use social media. Arvin suspects that the percentage of year 12 students at his college who use social media is less than the national percentage. He chooses a random sample of 20 students at his college and notes the number who use social media. He then carries out a test at the \(2 \%\) significance level.
  1. Find the rejection region for the test.
  2. Find the probability of a Type I error.
  3. Jimmy believes that the true percentage at Arvin's college is \(70 \%\). Assuming that Jimmy is correct, find the probability of a Type II error.
    If you use the following lined page to complete the answer(s) to any question(s), the question number(s) must be clearly shown.

Question 7(a):
AnswerMarks Guidance
AnswerMark Guidance
\(P(X \leqslant n)\) \((n \leqslant 20)\) attempted, using \(B(20,\, 0.95)\)M1 OE
\(P(X \leqslant 17)\) or \(P(X \leqslant 16)\) attempted, using \(B(20,\, 0.95)\)M1 OE
\((P(X \leqslant 17)) = 0.0755\) and \((P(X \leqslant 16)) = 0.0159\)A1 OE (0.925 and 0.984) both correct
Rejection region is \(X \leqslant 16\) or \(X < 17\)A1 Dependent on M1M1 and previous answers correct to at least 0.075/0.076 and 0.016 or 0.92/0.93 and 0.98. Correct unsupported answers of 0.0755 and 0.0159 OE scores M1M1A0
Question 7(b):
AnswerMarks Guidance
\(0.0159\)B1 FT *their* rejection region, from Binomial in \(a\), if $P(X \text{ in rejection region}) < 0.025
Total: 1 mark
Question 7(c):
AnswerMarks Guidance
Use of \(B(20, 0.7)\)M1
\(P(X > 16 \mid p = 0.7)\)M1 Correct method using \(B(20, 0.7)\)
\(= 0.107\)A1
Total: 3 marks
## Question 7(a):

| Answer | Mark | Guidance |
|--------|------|----------|
| $P(X \leqslant n)$ $(n \leqslant 20)$ attempted, using $B(20,\, 0.95)$ | M1 | OE |
| $P(X \leqslant 17)$ or $P(X \leqslant 16)$ attempted, using $B(20,\, 0.95)$ | M1 | OE |
| $(P(X \leqslant 17)) = 0.0755$ and $(P(X \leqslant 16)) = 0.0159$ | A1 | OE (0.925 and 0.984) both correct |
| Rejection region is $X \leqslant 16$ or $X < 17$ | A1 | Dependent on M1M1 and previous answers correct to at least 0.075/0.076 and 0.016 **or** 0.92/0.93 and 0.98. Correct unsupported answers of 0.0755 and 0.0159 OE scores M1M1A0 |

## Question 7(b):

$0.0159$ | B1 | FT *their* rejection region, from Binomial in $a$, if $P(X \text{ in rejection region}) < 0.025

**Total: 1 mark**

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## Question 7(c):

Use of $B(20, 0.7)$ | M1 |

$P(X > 16 \mid p = 0.7)$ | M1 | Correct method using $B(20, 0.7)$

$= 0.107$ | A1 |

**Total: 3 marks**
7 A national survey shows that $95 \%$ of year 12 students use social media. Arvin suspects that the percentage of year 12 students at his college who use social media is less than the national percentage. He chooses a random sample of 20 students at his college and notes the number who use social media. He then carries out a test at the $2 \%$ significance level.
\begin{enumerate}[label=(\alph*)]
\item Find the rejection region for the test.
\item Find the probability of a Type I error.
\item Jimmy believes that the true percentage at Arvin's college is $70 \%$. Assuming that Jimmy is correct, find the probability of a Type II error.\\

If you use the following lined page to complete the answer(s) to any question(s), the question number(s) must be clearly shown.
\end{enumerate}

\hfill \mbox{\textit{CAIE S2 2020 Q7 [8]}}