CAIE P1 2022 June — Question 3 5 marks

Exam BoardCAIE
ModuleP1 (Pure Mathematics 1)
Year2022
SessionJune
Marks5
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicArithmetic Sequences and Series
TypeShow quadratic equation in n
DifficultyModerate -0.3 This is a straightforward application of standard arithmetic progression formulas (S_n and nth term). Part (a) requires algebraic manipulation of the sum formula to reach a given result, while part (b) involves solving simultaneous equations. The question is slightly easier than average as it's purely procedural with no problem-solving insight required, though the algebra is non-trivial enough to avoid being trivial.
Spec1.04h Arithmetic sequences: nth term and sum formulae

3 An arithmetic progression has first term 4 and common difference \(d\). The sum of the first \(n\) terms of the progression is 5863.
  1. Show that \(( n - 1 ) d = \frac { 11726 } { n } - 8\).
  2. Given that the \(n\)th term is 139 , find the values of \(n\) and \(d\), giving the value of \(d\) as a fraction.

Question 3(a):
AnswerMarks Guidance
\(\frac{n}{2}[8+(n-1)d]=5863\) leading to \(n[8+(n-1)d]=11726\)B1 Must show a useful intermediate step. WWW AG.
leading to \((n-1)d=\frac{11726}{n}-8\)1 total
Question 3(b):
AnswerMarks Guidance
\(4+(n-1)d=139\) leading to \(\frac{11726}{n}-8=135\)\*M1 OE Use of correct \(u_n\) formula with expression from (a) or \(S_n\) formula to eliminate \(d\)
\(n=\frac{11726}{143}=82\)A1
\(81d=\frac{11726}{82}-8\)DM1 Substitute *their* \(n\) into a correct \(u_n\) or \(S_n\) formula
\(d=\frac{5}{3}\)A1 Accept \(\frac{138}{81}\) OE fraction only. If M0 DM0 scored then SC B1 B1 for correct \(n\) and \(d\) values only.
4 total
## Question 3(a):

$\frac{n}{2}[8+(n-1)d]=5863$ leading to $n[8+(n-1)d]=11726$ | **B1** | Must show a useful intermediate step. WWW AG.

leading to $(n-1)d=\frac{11726}{n}-8$ | **1 total** |

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## Question 3(b):

$4+(n-1)d=139$ leading to $\frac{11726}{n}-8=135$ | **\*M1** | OE Use of correct $u_n$ formula with expression from (a) or $S_n$ formula to eliminate $d$

$n=\frac{11726}{143}=82$ | **A1** |

$81d=\frac{11726}{82}-8$ | **DM1** | Substitute *their* $n$ into a correct $u_n$ or $S_n$ formula

$d=\frac{5}{3}$ | **A1** | Accept $\frac{138}{81}$ OE fraction only. If M0 DM0 scored then **SC B1 B1** for correct $n$ and $d$ values only.

**4 total**

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3 An arithmetic progression has first term 4 and common difference $d$. The sum of the first $n$ terms of the progression is 5863.
\begin{enumerate}[label=(\alph*)]
\item Show that $( n - 1 ) d = \frac { 11726 } { n } - 8$.
\item Given that the $n$th term is 139 , find the values of $n$ and $d$, giving the value of $d$ as a fraction.
\end{enumerate}

\hfill \mbox{\textit{CAIE P1 2022 Q3 [5]}}