CAIE P1 2022 June — Question 1 4 marks

Exam BoardCAIE
ModuleP1 (Pure Mathematics 1)
Year2022
SessionJune
Marks4
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicBinomial Theorem (positive integer n)
TypeSingle coefficient given directly
DifficultyModerate -0.5 This is a straightforward binomial expansion question requiring students to identify the correct term, apply the binomial coefficient formula, set up an equation with the given coefficient value, and solve a simple quadratic. While it involves multiple steps, each step is routine and the question follows a standard textbook pattern with no novel insight required.
Spec1.04a Binomial expansion: (a+b)^n for positive integer n

1 The coefficient of \(x ^ { 3 }\) in the expansion of \(\left( p + \frac { 1 } { p } x \right) ^ { 4 }\) is 144 .
Find the possible values of the constant \(p\).

Question 1:
AnswerMarks Guidance
AnswerMarks Guidance
\(4C1 \times p \times \frac{1}{p^3}x^3\)B1 OE; soi can be seen in an expansion
\(\frac{4}{p^2} = 144\)B1 OE; correct with correct power of \(p\) and only one \(p\) term
\(p = \pm\frac{1}{6}\)B1 B1 OE \(\pm\frac{2}{12}\) etc. Allow \(\pm 0.167\) for B1 B1; SC B1 for \(\pm\sqrt{\frac{1}{36}}\) B1 only
4
## Question 1:

| Answer | Marks | Guidance |
|--------|-------|----------|
| $4C1 \times p \times \frac{1}{p^3}x^3$ | **B1** | OE; soi can be seen in an expansion |
| $\frac{4}{p^2} = 144$ | **B1** | OE; correct with correct power of $p$ and only one $p$ term |
| $p = \pm\frac{1}{6}$ | **B1 B1** | OE $\pm\frac{2}{12}$ etc. Allow $\pm 0.167$ for B1 B1; **SC B1** for $\pm\sqrt{\frac{1}{36}}$ B1 only |
| | **4** | |

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1 The coefficient of $x ^ { 3 }$ in the expansion of $\left( p + \frac { 1 } { p } x \right) ^ { 4 }$ is 144 .\\
Find the possible values of the constant $p$.\\

\hfill \mbox{\textit{CAIE P1 2022 Q1 [4]}}