CAIE S1 2016 November — Question 3 8 marks

Exam BoardCAIE
ModuleS1 (Statistics 1)
Year2016
SessionNovember
Marks8
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicApproximating Binomial to Normal Distribution
TypeExact binomial then normal approximation (same context, different n)
DifficultyStandard +0.3 This is a straightforward application of binomial probability (part i) and normal approximation to binomial (part ii). Part (i) requires calculating P(X≥6) for X~B(7, 0.8), which is routine. Part (ii) is a standard textbook exercise in applying continuity correction for X~B(100, 0.2) approximated by N(20, 16). Both parts require only direct application of learned techniques with no problem-solving insight needed, making it slightly easier than average.
Spec2.04b Binomial distribution: as model B(n,p)2.04c Calculate binomial probabilities2.04d Normal approximation to binomial

3 On any day at noon, the probabilities that Kersley is asleep or studying are 0.2 and 0.6 respectively.
  1. Find the probability that, in any 7-day period, Kersley is either asleep or studying at noon on at least 6 days.
  2. Use an approximation to find the probability that, in any period of 100 days, Kersley is asleep at noon on at most 30 days.

Question 3:
Part (i):
AnswerMarks Guidance
Answer/WorkingMark Guidance
\(\text{Bin}(7, 0.8)\)M1 \(^7C_n\, p^n(1-p)^{7-n}\) seen
\(P(6,7) = {^7C_6}(0.8)^6(0.2)^1 + (0.8)^7\)M1 Correct unsimplified expression for \(P(6,7)\)
\(= 0.577\)A1 [3]
Part (ii):
AnswerMarks Guidance
Answer/WorkingMark Guidance
mean \(= 100 \times 0.2 = 20\)B1 Correct unsimplified mean and var
Var \(= 100 \times 0.2 \times 0.8 = 16\)
\(P(\text{at most } 30) = P\!\left(z < \dfrac{30.5 - 20}{\sqrt{16}}\right)\)M1 Standardising must have sq rt, their \(\mu\), variance
M1cc either 29.5 or 30.5
M1Correct area \(\Phi\), from final process
\(= P(z < 2.625) = 0.996\)A1 [5]
## Question 3:

### Part (i):

| Answer/Working | Mark | Guidance |
|---|---|---|
| $\text{Bin}(7, 0.8)$ | M1 | $^7C_n\, p^n(1-p)^{7-n}$ seen |
| $P(6,7) = {^7C_6}(0.8)^6(0.2)^1 + (0.8)^7$ | M1 | Correct unsimplified expression for $P(6,7)$ |
| $= 0.577$ | A1 [3] | |

### Part (ii):

| Answer/Working | Mark | Guidance |
|---|---|---|
| mean $= 100 \times 0.2 = 20$ | B1 | Correct unsimplified mean and var |
| Var $= 100 \times 0.2 \times 0.8 = 16$ | | |
| $P(\text{at most } 30) = P\!\left(z < \dfrac{30.5 - 20}{\sqrt{16}}\right)$ | M1 | Standardising must have sq rt, their $\mu$, variance |
| | M1 | cc either 29.5 or 30.5 |
| | M1 | Correct area $\Phi$, from final process |
| $= P(z < 2.625) = 0.996$ | A1 [5] | |

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3 On any day at noon, the probabilities that Kersley is asleep or studying are 0.2 and 0.6 respectively.\\
(i) Find the probability that, in any 7-day period, Kersley is either asleep or studying at noon on at least 6 days.\\
(ii) Use an approximation to find the probability that, in any period of 100 days, Kersley is asleep at noon on at most 30 days.

\hfill \mbox{\textit{CAIE S1 2016 Q3 [8]}}