CAIE S1 2016 November — Question 5 9 marks

Exam BoardCAIE
ModuleS1 (Statistics 1)
Year2016
SessionNovember
Marks9
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicPermutations & Arrangements
TypeArrangements with alternating patterns
DifficultyStandard +0.8 Part (a) requires systematic handling of alternating vowel/consonant arrangements with repeated letters (3 P's, 2 E's), demanding careful case analysis and application of permutation formulas. Part (b)(ii) adds a conditional constraint requiring complementary counting. While individual techniques are standard A-level, the combination of constraints and multi-step reasoning elevates this above routine exercises.
Spec5.01a Permutations and combinations: evaluate probabilities

5
  1. Find the number of different ways of arranging all nine letters of the word PINEAPPLE if no vowel (A, E, I) is next to another vowel.
  2. A certain country has a cricket squad of 16 people, consisting of 7 batsmen, 5 bowlers, 2 allrounders and 2 wicket-keepers. The manager chooses a team of 11 players consisting of 5 batsmen, 4 bowlers, 1 all-rounder and 1 wicket-keeper.
    1. Find the number of different teams the manager can choose.
    2. Find the number of different teams the manager can choose if one particular batsman refuses to be in the team when one particular bowler is in the team.

(a)
e.g. P*N*P*P*L
AnswerMarks
M1Multiply by \(5!\) in numerator
\(\frac{5!}{3! \cdot 2!} \times 6P_4 = 3600\)
AnswerMarks
M1Divide by \(3!\) or \(2!\)
M1Multiply by \(6P_4\) or equivalent
A1[4]
(b) (i)
\(\binom{7}{5} \times \binom{5}{4} \times \binom{2}{1} \times \binom{2}{1} = 420\)
AnswerMarks
M1Multiply 4 combinations of which three are correct
A1[2]
(ii)
Both in team: \(\binom{6}{4} \times \binom{4}{3} \times 2 \times 2 = 240\)
AnswerMarks
M1Evaluating both in team and subtracting from (i)
\(420 - 240 = 180\) ways
AnswerMarks
M1Follow-through their 420, their 240
A1[3]
OR
Bat in bowl out + bowl in bat out + both out
\(= \binom{6}{4} \times \binom{4}{3} \times 2 \times 2 + \binom{6}{5} \times \binom{4}{3} \times 2 \times 2 + \binom{6}{5} \times \binom{4}{4} \times 2 \times 2\)
\(= 60 + 96 + 24 = 180\) ways
AnswerMarks
M1Summing 2 or 3 options not both in team
A12 or 3 options correct, unsimplified
A1Correct answer from correct working
OR
Bat in bowl out + bat out
\(= 60 + \binom{6}{5} \times \binom{5}{4} \times 2 \times 2 = 60 + 120 = 180\) ways
AnswerMarks
M1As above, or bowl in bat out + bowl out
A1 A1[3]
**(a)**

e.g. P*N*P*P*L

M1 | Multiply by $5!$ in numerator

$\frac{5!}{3! \cdot 2!} \times 6P_4 = 3600$

M1 | Divide by $3!$ or $2!$

M1 | Multiply by $6P_4$ or equivalent

A1 | [4]

**(b) (i)**

$\binom{7}{5} \times \binom{5}{4} \times \binom{2}{1} \times \binom{2}{1} = 420$

M1 | Multiply 4 combinations of which three are correct

A1 | [2]

**(ii)**

Both in team: $\binom{6}{4} \times \binom{4}{3} \times 2 \times 2 = 240$

M1 | Evaluating both in team and subtracting from (i)

$420 - 240 = 180$ ways

M1 | Follow-through their 420, their 240

A1 | [3]

**OR**

Bat in bowl out + bowl in bat out + both out

$= \binom{6}{4} \times \binom{4}{3} \times 2 \times 2 + \binom{6}{5} \times \binom{4}{3} \times 2 \times 2 + \binom{6}{5} \times \binom{4}{4} \times 2 \times 2$

$= 60 + 96 + 24 = 180$ ways

M1 | Summing 2 or 3 options not both in team

A1 | 2 or 3 options correct, unsimplified

A1 | Correct answer from correct working

**OR**

Bat in bowl out + bat out

$= 60 + \binom{6}{5} \times \binom{5}{4} \times 2 \times 2 = 60 + 120 = 180$ ways

M1 | As above, or bowl in bat out + bowl out

A1 A1 | [3]

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5
\begin{enumerate}[label=(\alph*)]
\item Find the number of different ways of arranging all nine letters of the word PINEAPPLE if no vowel (A, E, I) is next to another vowel.
\item A certain country has a cricket squad of 16 people, consisting of 7 batsmen, 5 bowlers, 2 allrounders and 2 wicket-keepers. The manager chooses a team of 11 players consisting of 5 batsmen, 4 bowlers, 1 all-rounder and 1 wicket-keeper.
\begin{enumerate}[label=(\roman*)]
\item Find the number of different teams the manager can choose.
\item Find the number of different teams the manager can choose if one particular batsman refuses to be in the team when one particular bowler is in the team.
\end{enumerate}\end{enumerate}

\hfill \mbox{\textit{CAIE S1 2016 Q5 [9]}}