CAIE S1 2012 November — Question 5 12 marks

Exam BoardCAIE
ModuleS1 (Statistics 1)
Year2012
SessionNovember
Marks12
PaperDownload PDF ↗
Mark schemeDownload PDF ↗
TopicNormal Distribution
TypeRounded or discrete from continuous
DifficultyStandard +0.3 This is a straightforward application of normal distribution techniques with standard table lookups. Part (i) requires understanding rounding (finding P(83.5 < X < 84.5)), part (ii) combines normal probability with binomial calculation, and part (iii) is a reverse normal table lookup. All are routine procedures slightly above average difficulty due to the multi-step nature and discrete-from-continuous conversion.
Spec2.04b Binomial distribution: as model B(n,p)2.04e Normal distribution: as model N(mu, sigma^2)2.04f Find normal probabilities: Z transformation

5 The random variable \(X\) is such that \(X \sim \mathrm {~N} ( 82,126 )\).
  1. A value of \(X\) is chosen at random and rounded to the nearest whole number. Find the probability that this whole number is 84 .
  2. Five independent observations of \(X\) are taken. Find the probability that at most one of them is greater than 87.
  3. Find the value of \(k\) such that \(\mathrm { P } ( 87 < X < k ) = 0.3\).

AnswerMarks Guidance
(i) \([\frac{1}{2} \times 12(7^2 - 3^2)]\)M1 For using KE = \(\frac{1}{2}m(v_B^2 - v_A^2)\)
Increase is 240 JA1 2 marks total
(ii)M1 For using \(mgh\) = KE gain
\(12g \times AB\sin10° = 240\)A1ft
Distance is 11.5 mA1 3 marks total
SR for candidates who avoid 'hence' (max 2/3): For using Newton's Second Law and \(v^2 = u^2 + 2as\): \([12g\sin10° = 12a\) then \(7^2 = 3^2 + 2(g\sin10° \times AB)]\)M1 11.5 m
(iii)
\(F \times 11.5\cos10° = 240\) or \(F\cos10° - 12g\sin10° = 0\)A1ft
Magnitude is 21.2 NA1 3 marks total
**(i)** $[\frac{1}{2} \times 12(7^2 - 3^2)]$ | M1 | For using KE = $\frac{1}{2}m(v_B^2 - v_A^2)$

Increase is 240 J | A1 | 2 marks total

**(ii)** | M1 | For using $mgh$ = KE gain

$12g \times AB\sin10° = 240$ | A1ft |

Distance is 11.5 m | A1 | 3 marks total

| | | SR for candidates who avoid 'hence' (max 2/3): For using Newton's Second Law and $v^2 = u^2 + 2as$: $[12g\sin10° = 12a$ then $7^2 = 3^2 + 2(g\sin10° \times AB)]$ | M1 | 11.5 m | A1

**(iii)** | | | For using $F(AB)\cos10° =$ PE gain or for using Newton's 2nd law with $a = 0$

$F \times 11.5\cos10° = 240$ or $F\cos10° - 12g\sin10° = 0$ | A1ft |

Magnitude is 21.2 N | A1 | 3 marks total

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5 The random variable $X$ is such that $X \sim \mathrm {~N} ( 82,126 )$.\\
(i) A value of $X$ is chosen at random and rounded to the nearest whole number. Find the probability that this whole number is 84 .\\
(ii) Five independent observations of $X$ are taken. Find the probability that at most one of them is greater than 87.\\
(iii) Find the value of $k$ such that $\mathrm { P } ( 87 < X < k ) = 0.3$.

\hfill \mbox{\textit{CAIE S1 2012 Q5 [12]}}